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3 years ago

Plss help if can!! Thanks!

Mathematics

1 answer:

Novosadov [1.4K]3 years ago

5 0

The first one is 2 the second one is 3

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Many fences in a rectangular area for his dog to play in the backyard. The area measures 35 yards by 45 yards .What is the lengt

klasskru [66]

Answer:

ITS 160

Step-by-step explanation:

6 0

3 years ago

What is the solution set for this inequality? -8x + 40>-16

andreev551 [17]

Answer:

x<7

Step-by-step explanation:

-8x+40>-16

8 0

2 years ago

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A class’s test scores are normally distributed if the average score 60 and the standard deviation is 7 choose the spots where th

Brrunno [24]

Answer:

Step-by-step explanation:

We are given that a class's test scores are normally distributed with an average score of 60.

We know that the curve of a normal distribution is symmetric about its mean.

60-14=46

60+14=74

Hence, the point 46 lies to the left of the mean and 74 lies to the right of the mean, and the two points have the same function value.

5 0

2 years ago

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Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).

spayn [35]

The Bernoulli distribution is a distribution whose random variable can only take 0 or 1

The value of E(x2) is p
The value of V(x) is p(1 - p)
The value of E(x79) is p

<h3>How to compute E(x2)</h3>

The distribution is given as:

p(0) = 1 - p

p(1) = p

The expected value of x2, E(x2) is calculated as:

$E(x^2) = \sum x^2 * P(x)$

So, we have:

$E(x^2) = 0^2 * (1- p) + 1^2 * p$

Evaluate the exponents

$E(x^2) = 0 * (1- p) + 1 * p$

Multiply

$E(x^2) = 0 +p$

Add

$E(x^2) = p$

Hence, the value of E(x2) is p

<h3>How to compute V(x)</h3>

This is calculated as:

$V(x) = E(x^2) - (E(x))^2$

Start by calculating E(x) using:

$E(x) = \sum x * P(x)$

So, we have:

$E(x) = 0 * (1- p) + 1 * p$

$E(x) = p$

Recall that:

$V(x) = E(x^2) - (E(x))^2$

So, we have:

$V(x) = p - p^2$

Factor out p

$V(x) = p(1 - p)$

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

$E(x^{79}) = \sum x^{79} * P(x)$

So, we have:

$E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p$

Evaluate the exponents

$E(x^{79}) = 0 * (1- p) + 1 * p$

Multiply

$E(x^{79}) = 0 + p$

Add

$E(x^{79}) = p$

Hence, the value of E(x79) is p

Read more about probability distribution at:

brainly.com/question/15246027

5 0

2 years ago

Pls help me I know this is easy I’m just not smart

skelet666 [1.2K]

Answer:

Step-by-step explanation:

Given :

5c+cd where, $C=\frac{1}{5}$ and d=15

Now,

5× $\frac{1}{5} +\frac{1}{5} (15)$

=1+3

Answer is 4

3 0

3 years ago