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Artyom0805 [142]

3 years ago

6

Which equation represents the relationship between x and y in the table below?

1 answer:

mart [117]3 years ago

5 0

A does
x is going up 2
y is going up 1
this means the slope is 1/2
the y intercept is 1 because when x = 0 y = 1

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What is the first step to graphing this equation by the method of creating a table of values?

VikaD [51]

If you solve for x answer is x=y/5+7/5

4 0

3 years ago

The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 48,637 miles, with a variance

Brut [27]

Answer:

$P(x < -778) = 0$

Step-by-step explanation:

Given

$\bar x = 48673$

$\sigma^2 = 11282880$

$n = 143$

Required

$P(x$

First, we calculate the z score

$z = \frac{x}{\sqrt{\sigma^2}/n}$

So, we have:

$z = \frac{-778}{\sqrt{11282880}/143}$

$z = \frac{-778}{3359.0/143}$

$z = \frac{-778}{23.49}$

$z = -33.12$

So:

$P(x < -778) = P(z < -33.12)$

From z score probability, we have:

$P(x < -778) = 0$

4 0

3 years ago

Math Help PLEASE! ASAP

alekssr [168]

1. 50% of the budget is spent on other:
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Answer is $2,500

2. a full circle = 360 degrees
40% = 0.4
360 * 0.4 =144 degrees

3. third one shows the correct circle graph

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4 years ago

The area of a rectangle is 35 ft squared , and the length of the rectangle is 3 ft more than twice the width. find the dimension

andrey2020 [161]

Are there any answer choices

7 0

4 years ago

In △ABC acute angles are in the ratio 5:1, i.e. ∠BAC:∠ABC = 5:1. If CH is an altitude and CL is an angle bisector, find m∠HCL.

tekilochka [14]

If $m\angle BAC:m\angle ABC=5:1,$ then $m\angla BAC=(5x)^{\circ},\ m\angle ABC=x^{\circ}.$

The sum of the measures of the interior angles of the triangle is always 180°, then

$m\angle ACB=180^{\circ}-x^{\circ}-(5x)^{\circ}=180^{\circ}-(6x)^{\circ}.$

Since CL is bisector, then

$m\angle BCL=m\angle ACL=\dfrac{180^{\circ}-(6x)^{\circ}}{2}=90^{\circ}-(3x)^{\circ}.$

Consider right triangle ACH. In this triangle

$m\angle ACH=180^{\circ}-90^{\circ}-(5x)^{\circ}=90^{\circ}-(5x)^{\circ}.$

Now angle HCL has measure

$m\angle HCL=m\angle ACL-m\angle ACH=90^{\circ}-(3x)^{\circ}-(90^{\circ}-(5x)^{\circ})=(2x)^{\circ}=2m\angle ABC.$

Answer: $m\angle HCL=2m\angle ABC.$

6 0

4 years ago