Answer:
Contents Home Courses University of California Davis UCD Chem 2C: General Chemistry III UCD Chem 2C: Larsen Text Unit 4: Chemical Kinetics Expand/collapse global location
4.7: Collision Theory
Last updatedSep 3, 2020
4.6: Using Graphs to Determine (Integrated) Rate Laws
4.8: Temperature and Rate
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Learning Objectives
Molecules must collide in order to react.
In order to effectively initiate a reaction, collisions must be sufficiently energetic (kinetic energy) to break chemical bonds; this energy is known as the activation energy.
As the temperature rises, molecules move faster and collide more vigorously, greatly increasing the likelihood of bond breakage upon collision.
Collision theory explains why different reactions occur at different rates, and suggests ways to change the rate of a reaction. Collision theory states that for a chemical reaction to occur, the reacting particles must collide with one another. The rate of the reaction depends on the frequency of collisions. The theory also tells us that reacting particles often collide without reacting. For collisions to be successful, reacting particles must (1) collide with (2) sufficient energy, and (3) with the proper orientation.
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C. Chemical properties always change depending on temperature or pressure
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Answer:A molecule is formed when two or more atoms join together chemically.
Explanation:
Answer:

Explanation:
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In this case, since the study of the bond energy allows us to compute the enthalpies of some reactions, for this combination reaction by which ammonia is yielded, we understand the enthalpy of reaction equals the enthalpy of formation of ammonia, and, in terms of the bonds energy we can write:

Whereas the bonds enthalpy of those bonds that get broken cover the N≡N and the three H-H bonds at the reactants side and the enthalpy of those bonds that are formed cover the six N-H bonds at the products; which means we obtain:

Which differs from the theoretical value that is -46 kJ/mol.
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