Answer:
The right statement is "The percent transmittance of light, %T, will be higher for Sample 1 compared to Sample 2."
Explanation:
The Beer-Lambert Law states that the absorbance is directly proportional to the concentration of the substance.
Absorbance = εLc
ε: molar absorptivity coeficient
L: optical path length
c: molar concentration
Therefore, if ε and L are the same, the higher the concentration, the higher the absorbance and the lower the transmitance.
Since sample 1 has a higher concentration of CuSO₄ than sample 2, sample 1 has a higher absorbance and lower percent transmittance.
Answer:
functional group - carboxylic
molecule name- propanic acid
I don’t care about it tbh like I don’t even care about that stuff but the answer is 29272728
