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3 years ago

Evaluate -(2^6)(2^3)

Mathematics

1 answer:

valina [46]3 years ago

7 0

Answer:

- (2^9)

Step-by-step explanation:

-(2^6)(2^3)

We know a^b * a^c = a^( b+c)

- ( 2 ^ (6+3))

- (2^9)

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4. A classmate is having difficulty finding the measures of <BGE and <BDG in the diagram on the right. What mathematical a

Firlakuza [10]

Part 1) Find the measures of angle BGE
we know that
The inscribed angle measures half of the arc it comprises.
so
angle BGE=(1/2)*[arc EB]

Part 2) Find the angle BDG
we know that
The measure of the external angle is the semi-difference of the arcs that it covers.
so
angle BDG=(1/2)*[arc GEB-arc GB]

8 0

3 years ago

To track the fish population in a certain area a sample of 35 fish were tagged and released.Later another sample was caught and

olga nikolaevna [1]

Answer:

Step-by-step explanation:

The question says that the fish population of an area is being tracked and a certain of 35 were collected,tagged and released.

Later another sample was collected and it revealed that 13% of those fishes caught were the ones tagged previously.

The estimated number of fishes in that area will be:

Let X= number of fishes available in that area

13 percent of fishes caught at the second sample collection were tagged

Number of fishes collected are 35

13/100×X= 35

X= 3500/13

X= 269

The number of fishes in the pond is around 269

7 0

2 years ago

What is the midpoint and distance between points P(3,5) and Q(7,5)

storchak [24]

The formula of a midpoint:

$M\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)$

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have the points P(3, 5) and Q(7, 5). Substitute:

$x=\dfrac{3+7}{2}=\dfrac{10}{2}=5\\\\y=\dfrac{5+5}{2}=\dfrac{10}{2}=5$

$d=\sqrt{(5-5)^2+(7-3)^2}=\sqrt{0^2+4^2}=\sqrt{4^2}=4$

<h3>Answer:</h3><h3>Midpoint = (5, 5)</h3><h3>Distance = 4</h3>

4 0

3 years ago

Rewrite the following quadratic function in vertex form. Then, determine if it has a maximum or minimum and say what that value

alexira [117]

Discussion

1. Put brackets around the first two terms

y = (-x^2 + 6x) + 5

2. Take out the common factor of -1

y = -(x^2 - 6x) + 5

3. Inside the brackets, take 1/2 of - 6 and square it

y = -(x^2 - 6x + ( - 6 / 2)^2 ) + 5

y = -(x^2 - 6x + (- 3)^2 ) ) + 5

y = -(x^2 - 6x + 9 ) + 5

Note: Step 3 is very long. Make sure you work your way through it

4. You have added 9 inside the brackets. <em><u>It is actually - 9. So add 9 outside to balance the equation out. </u></em> This is the key step. Make sure you understand it.

y = - (x^2 - 6x + 9) + 5 + 9

5. Express the brackets as a square.

y = - (x + 3)^2 + 14

Discussion

The equation is now in vertex form. The minus tells you that the equation is a maximum. The maximum is located at ( - 3, 14 )

A graph follows to show the results.