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Aleonysh [2.5K]
2 years ago
5

Y-4=0 in standard form

Mathematics
1 answer:
wolverine [178]2 years ago
7 0
Standard form : Ax + By = C

y - 4 = 0
y = 4...this is a horizontal line and a horizontal line has a 0 slope

so in standard form, ur equation is : 0x + y = 4
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A bag contains 6 nickels and 14 pennies. What is the ratio, written in lowest terms, of nickels to the total number of coins in
VLD [36.1K]
There are 6 nickels and 14 pennies.
There are 20 total coins.

The ratio of nickels to coins is 6:20.
Both of these are divisible by 2, so we can reduce this to 3:10.
4 0
3 years ago
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Which board geometrically represents 4x2 – 1 using algebra tiles? An algebra tile configuration showing only the product spot, w
Lady bird [3.3K]

Answer: it’s the second one

Step-by-step explanation:

9 0
3 years ago
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What's the surface area ratio &amp; the volume ratio??<br><br> please help me ASAP!!
Ulleksa [173]

Answer:

Step-by-step explanation:

Volumes of two spheres A and B = 648 cm³ and 1029 cm³

Things to remember:

1). Scale factor of two objects = \frac{r_1}{r_2} [r_1 and r_2 are the radii of two circles]

2). Area scale factor = \frac{(r_1)^2}{(r_2)^2}

3). Volume scale factor = \frac{(r_1)^3}{(r_2)^3}

Volume scale factor Or Volume ratio = \frac{V_A}{V_B}

                         \frac{(r_1)^3}{(r_2)^3}= \frac{648}{1029}

                         \frac{r_1}{r_2}=\sqrt[3]{\frac{648}{1029} }

                         \frac{r_1}{r_2}=\frac{6(\sqrt[3]{3})}{7(\sqrt[3]{3})}

                        \frac{r_1}{r_2}=\frac{6}{7}

Therefore, scale factor = \frac{r_1}{r_2}=\frac{6}{7}

                                      ≈ 6 : 7

Area scale factor Or area ratio = (\frac{r_1}{r_2})^2=(\frac{6}{7})^2

                                                   = \frac{36}{49}

                                                   ≈ 36 : 49

Volume scale factor or Volume ratio = \frac{648}{1029}

                                                             = \frac{216}{343}

                                                             ≈ 216 : 343

4 0
3 years ago
Dada a Matriz A= [1 -2 1 ][-3 1 4] [0 6 8] , escreva uma matriz B diferente de A, tal que detA =detB.
Mariulka [41]

Use o fato de que o determinante de qualquer matriz quadrada é o mesmo da sua transposta.

\mathbf A=\begin{bmatrix}1&-2&1\\-3&1&4\\0&6&8\end{bmatrix}

\mathbf B=\mathbf A^\top=\begin{bmatrix}1&-3&0\\-2&1&6\\1&4&8\end{bmatrix}

3 0
3 years ago
Could someone explain how you would solve this? I really don't understand it.
nlexa [21]
Because of rules of geometry we know that a+b=180 degrees so we can add the equations together and set that equal to 180 and solve
6x-48+4x+38=180
subtract 38 from both sides and add 48 to both sides
then add like terms
10x=170
and divide by 10 to get 
x=17
7 0
3 years ago
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