Answer:
C
Step-by-step explanation:
- Reform the first graph: -3x + 3y = 12; 3y = 12 + 3x; y = 4 + x; y = x + 4
- Compare y = x + 4 and y = x + 4: they are equal, thus the same slope (1) and the same y-intercept (4)
The perimeter of a triangle can be found by adding up all the sides
so the perimeter is :
5 + 8 + x =
13 + x <==
I think we can use the identity sin x/2 = sqrt [(1 - cos x) /2]
cos x - sqrt3 sqrt ( 1 - cos x) /sqrt2 = 1
cos x - sqrt(3/2) sqrt(1 - cos x) = 1
sqrt(3/2)(sqrt(1 - cos x) = cos x - 1 Squaring both sides:-
1.5 ( 1 - cos x) = cos^2 x - 2 cos x + 1
cos^2 x - 0.5 cos x - 0.5 = 0
cos x = 1 , -0.5
giving x = 0 , 2pi, 2pi/3, 4pi/3 ( for 0 =< x <= 2pi)
because of thw square roots some of these solutions may be extraneous so we should plug these into the original equations to see if they fit.
The last 2 results dont fit so the answer is x = 0 , 2pi Answer
1.) Plug x and y to the formula:
4(2) + 1/3(3)^2
2.) Simplify
8 + 1/3(9)
= 8 + 3
= 11
Hope this helped!!!
