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MA_775_DIABLO [31]
3 years ago
12

If x and y are negative integers and x – y = 1, what is the least possible value for xy?

Mathematics
1 answer:
ra1l [238]3 years ago
5 0
X=y+1
Least possible value for y(y+1)? Well, it appears for y halfway between the roots (you know what a parabola is, don't you?). That y is -0.5, so let's calculate -0.5*0.5, which is -0.25.
The least possible value is -\frac{1}4
Well, not really :)) The two values must be both negative, so we can't take one of them to be 0.5! As we lower the values, however, the product grows, reaching 0 when x=0 and y=-1, and further increasing as x and y lower. Thus, we would actually take x=0 and y=-1.
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How many terms are in the algebraic expression -7 + 12x4 - 5y8 + x?
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Sue spent 1 hour 19 minutes less than Jared reading last week. Jared spent 45 minutes less than Pete. Pete spent 3 hours reading
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Sue spend 56 minutes in reading.

<h3>What is Unitary Method?</h3>

Unitary method is a process by which we find the value of a single unit from the value of multiple units and the value of multiple units from the value of a single unit.

Sue spent 1 hour 19 minutes less than Jared

Lucas spent 45 minutes less than Pete.

Pete spent 3 hours reading.

Since, pete spent 3 hours. So, Jared spent

= 3 hours or (180 minutes) - 45 minutes

= 2 hours 15 minutes.

Now, Seu spent = 2 hrs 15 minutes - 1 hour 19 minutes  

                           = 56 minutes

Learn more about unitary method here:

brainly.com/question/22056199

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6 0
2 years ago
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3 years ago
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a 5 inch tall bamboo shoot doubles in height every 3 days. if the equation, y=ab^x where x is the number of doubling periods, re
Lemur [1.5K]
X-doubling periods
Y-height of bamboo
Y=ab^x

1) make a table of values
X Y
1 5
2 10
3 20

2) write equations and substitute
5=ab^1 —> a=5/b^1 —> a=5/b
10=ab^2

Substitute into second equation

10=(5/b)*b^2
10=5b^2/b
10=5b
b=2

Substitute back in

b=2
10=a*2^2
10=4a
a=5/2

End equation:
Y=5/2*2^x


3 0
3 years ago
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