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3 years ago

If x and y are negative integers and x – y = 1, what is the least possible value for xy?

1 answer:

5 0

X=y+1
Least possible value for y(y+1)? Well, it appears for y halfway between the roots (you know what a parabola is, don't you?). That y is -0.5, so let's calculate -0.5*0.5, which is -0.25.
The least possible value is $-\frac{1}4$
Well, not really :)) The two values must be both negative, so we can't take one of them to be 0.5! As we lower the values, however, the product grows, reaching 0 when x=0 and y=-1, and further increasing as x and y lower. Thus, we would actually take x=0 and y=-1.

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I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago

The product of nine and a number is added to six the result is 24 what is the number

Andru [333]

Hello!

We can make an equation based on what we know

The product of 9 and a number is

9 * x

Added to six

9 * x + 6

Gives the result of 24

9 * x + 6 = 24

Now you solve it algebraically

Subtract 6 from both sides

9 * x = 18

Divide both sides by 9

x = 2

The answer is 2

Hope this helps!

8 0

3 years ago

One glass of milk provides 305mg of calcium. Maggie drinks one glass of milk every morning. How many grams of calcium does Maggi

Komok [63]

She drinks 4.27 grams on calcium in 14 days at one glass of milk containing 14 mg per day

8 0

3 years ago

Read 2 more answers

A quadratic function is described by the equation f(x) = (x - 3) ^ 2 Which statement about the graph of the function is true?

Bond [772]

Answer: A) The only zero of the function is 3 which is where the graph of the function intersects the x-axis

Step-by-step explanation:

Remember, a quadratic function which has roots x = a, and x = b, can be written as:

p(x) = A*(x - a)*(x - b)

Where A is the leading coefficient. This is the factorized form of a quadratic.

We have the function:

f(x) = (x - 3)^2

Now, we could rewrite this as:

f(x) = (x - 3)*(x - 3) = 1*(x - 3)*(x - 3)

Then we wrote f(x) in its factorized form, from this, we can see that the roots of the function are x = 3, and x = 3 (we have the same root two times)

Then the only root of f(x) is x = 3.

Remember that a root (also called a zero) is the value of x where the function intersects the x-axis. then the correct option here is:

A) The only zero of the function is 3 which is where the graph of the function intersects the x-axis

4 0

3 years ago

What is 9.8846387057 to the nearest whole number

alukav5142 [94]

Answer:

Step-by-step explanation:

The . 8 would round up making the 9 a 10

So the answer is ten

7 0

3 years ago

Read 2 more answers