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Sveta_85 [38]
3 years ago
6

The function f(x) is given by the set of ordered pairs. {(1,0), (–10,2), (0,6), (3,17), (–2,–1)} Which equation is true?

Mathematics
2 answers:
mina [271]3 years ago
8 0

Answer:C

Step-by-step explanation:

Mazyrski [523]3 years ago
7 0

Answer:

y = -6x + 6

Step-by-step explanation:

To make an equation you need to find the slope first

To do that use the expression y2-y1/x2-x1 (-6)

Now plug that in to y = mx + b

Lastly you substitute any coordinate and find b

y = -6x + 6

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2. The cone has a radius of 30 mm and slant height of 34 mm. What is the height h for this cone?​
Flura [38]

Answer:

h = 16

Step-by-step explanation:

By applying the Pythagorean Theorem, the slant height is given by the formula:

\sqrt{r^2+h^2}

34 = \sqrt{30^2 + h^2}

34^2 = 30^2 + h^2

1156 = 900 + h^2

256 = h^2

h = \sqrt{256}

h = 16

6 0
3 years ago
How to slove step by step
wariber [46]
\frac{x+3}{12} = \frac{2}{7}

Multiply both sides by 12, so that we get rid of the fraction in x.

12 · (x+3)/12 = 2/7 · 12

Simplify.

x + 3 = 24/7

Then, subtract 3 from both sides, so that "x" gets isolated.

x = 24/7 - 3

Turn "3" into an improper fraction so that we could find the value of x easier.

3 = 21/3

So :

x = 24/7 - 21/7

Simplify.

x = 3/7

~Hope this helps!~


7 0
3 years ago
An object is launched from a platform.
tankabanditka [31]

Answer:

  10

Step-by-step explanation:

Ground level is where h = 0, so solve the equation ...

  h(x) = 0

  -5(x -4)^2 +180 = 0 . . . . substitute for h(x)

  (x -4)^2 = 36 . . . . . . . . . . divide by -5, add 36

  x -4 = 6 . . . . . . . . . . . . . . positive square root*

  x = 10 . . . . . . add 4

The object will hit the ground 10 seconds after launch.

_____

* The negative square root also gives an answer that satisfies the equation, but is not in the practical domain. That answer would be x = -2. The equation is only useful for time at and after the launch time: x ≥ 0.

8 0
3 years ago
she brought 7/8 as much in april  as she did in october and july combined october has 3/4 and july has 1 and 1 fourth
Leno4ka [110]
What's the question?

4 0
3 years ago
Find the intersection points of the linear and quadratic functions shown below f(x)=2x-5 g(x)= x2+2x-21
Mice21 [21]

Answer:

(-4,-13) and (4,3) the intersection points.

Step-by-step explanation:

Intersection point of two functions is a common point which satisfies both the functions.

Given functions are,

f(x)=2x-5

g(x)=x^2+2x-21

For a common point of these functions,

f(x)=g(x)

2x-5=x^2+2x-21

-5=x^2-21

0=x^2-16

x^2=16

x=-4,4

For x=-4,

f(-4)=g(-4)=2(-4)-5

                       =-13

For x=4,

f(4)=g(4)=2(4)-5

                  =3

Therefore, (-4,-13) and (4,3) the intersection points.

3 0
3 years ago
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