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Goshia [24]
3 years ago
9

Newton's Third Law of Motion relates to action and reaction. Which of the following scenarios accurately names the correct actio

n and reaction pair to apply to Newton's Third Law? A. A skateboard moving (action) after being pushed (reaction) B. An ax being used to hit wood (action) and the wood splitting after being hit by the ax (reaction) C. A car accelerating forward (action) after the driver pushes the acceleration pedal (reaction) D. An arrow hitting a tree (action) after being launched (reaction
Physics
2 answers:
timama [110]3 years ago
6 0

Choice-B correctly identifies an action and its consequence, but it sure isn't an example of Newton's 3rd law. And neither are any of the other choices.

Olin [163]3 years ago
3 0

Answer:

(B)

Explanation:

While some of the other scenarios make sense to match with Newton's Third Law of Motion, their reaction and actions are in the wrong order.

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What is the average velocity of a bowling ball that moves down the lane 8 meters in 4 seconds?​
Tema [17]

Answer: 2m/s

Explanation:

V avg = Displacement / time

Displacement is 8

Time is 4

V avg = 2

8 0
3 years ago
In recent years, astronomers have found planets orbiting nearby stars that are quite different from planets in our solar system.
BartSMP [9]

Answer:

The value of g in Kepler-12b is 3.85 m/s^{2}

Explanation:

To determine the value of g at Kepler-12b it is necessary to combine the equation of the weight and the equation for the Universal law of gravity:

W = m.g  (1)

Where m is the mass and g is the value of the gravity

F = G \frac{M.m}{R^{2}}  (2)

Equation (1) and equation (2) will be equal, since the weight is a force acting on the object as a consequence of gravity:

m.g = G \frac{M.m}{R^{2}}  (3)

Then g will be isolated from equation 3:

g = G \frac{M.m}{m.R^{2}}

g = \frac{G.M}{R^{2}}  (4)

The radius of Jupiter has a value of 69911000 meters, so its diameter can be determined by:

d = 2R (5)

Where d and R are the diameter and radius of Jupiter

d_{jupiter} = 2(69911000 m)

d_{jupiter} = 139822000 m

Procedure for finding the radius of Kepler-12b:

For the case of Kepler-12b it has a diameter that is 1.7 times that of Jupiter

d_{Kepler-12b} = 1.7(d_{jupiter})

d_{Kepler-12b} = 1.7(139822000 m)

d_{Kepler-12b} = 237697400 m

By means of equation 5 the radius of Kepler-12b can be known:

R_{Kepler-12b} = \frac{d}{2}

R_{Kepler-12b} = \frac{237697400 m}{2}

R_{Kepler-12b} = 118848700 m

Procedure for finding the mass of Kepler-12b:

The mass of Jupiter has a value of 1.898x10^{27} kilograms

For the case of Kepler-12b it has a mass that is 0.43 times that of jupiter

m_{Kepler-12b} = 0.43(m_{jupiter})

m_{Kepler-12b} = 0.43(1.898x10^{27} Kg)

m_{Kepler-12b} = 8.161x10^{26} Kg

The value of g in Kepler-12b can be found by replacing its radius and mass in equation 4:

g = \frac{(6.67x10^{-11} N.m^{2}/Kg^{2})(8.161x10^{26} Kg)}{(118848700 m)^{2}}

g = 3.85 m/s^{2}

Hence, in Kepler-12b the gravity has a value of 3.85 m/s^{2}

8 0
3 years ago
What is density? Write a formula by showing the relation of mass density and volume​
slava [35]

Answer: below

Explanation: Density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume

7 0
3 years ago
An object is moving to the left with a constant speed. What can be concluded about the forces acting upon the object?
MariettaO [177]

Answer: sum of forces is zero

Explanation: acording to the newton first law you can say that the sum of the forces acting over the object is zero no matter the direction of movement

good luck

mario

8 0
3 years ago
Light of wavelength 633 nm falls on a single slit 0.5 mm wide and forms a diffraction pattern on a screen 1.0 m away from the sl
andrey2020 [161]

Answer:

The position of the first dark spot on the positive side of the central maximum is 1.26 mm.

Explanation:

Given that,

Wavelength of light is 633 nm.

Slit width, d = 0.5 mm

The diffraction pattern forms on a screen 1 m away from the slit. We need to find the position of the first dark spot on the positive side of the central maximum.

For destructive interference :

\dfrac{dY}{D}=n\lambda

Y is the distance of the minima from central maximum

Here, n = 1

Y=\dfrac{n\lambda D}{d}\\\\Y=\dfrac{1\times 633\times 10^{-9}\times 1}{0.5\times 10^{-3}}\\\\Y=0.00126\ m\\\\Y=1.26\times 10^{-3}\ m\\\\Y=1.26\ mm

So, the position of the first dark spot on the positive side of the central maximum is 1.26 mm.

4 0
3 years ago
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