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PolarNik [594]
3 years ago
12

Which of the following situations would cause the greatest decrease in the motion of molecules in a system?

Physics
2 answers:
vredina [299]3 years ago
6 0
The answer is A. <span>Q = -50 J, W = -50 J. A decrease in the motion of molecules in a system can be interpreted as a decrease or release in energy which means that energy should be negative. For the formula of energy:

U = Q + W

U is negative for the case of A. This gives the greatest decrease in the molecules' motion.</span>
astra-53 [7]3 years ago
6 0

Answer:

a

Explanation:

Now, i will consider that W and A refers to the work and heat done/applied to the system  

Always Q is related to the heat, so if Q is positive this means that the temperature of the system increase if Q is negative this means that heat is extracted from the system, and the temperature decreases, which implies that the motion of the particles decreases.

For the work is the same, if the applied work is positive, then the energy of the system increments (suppose a gas inside a piston, if you compress the piston the work is positive, and now the particles are close together, wich increments the temperature of the gas)

If the work is negative, this means that the system does the work, so the energy decreases, and also the motion of the particles, so the correct option A

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The MCB of a rupas room is tripped and keeps on tripping again and again, and if it is a domestic circuit, what could be the reason for this phenomenon?

The reason could be a short circuit which is resulting in higher level of currents to pass through the MCB which is resulting in trip every time.

OR

The MCB is faulty and might need a replacement.

To Diagnose the problem further more.

Turn off all the switches in rupas room and then try turning on the MCB. If it trips again then MCB is faulty (Subjective to the fact there everything was normal before this issue and no signs of short circuit or spark in wiring were observed)

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3 years ago
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What is heat flow?

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8 0
2 years ago
Suppose that the electric field in the Earth's atmosphere is E = 8.60 101 N/C, pointing downward. Determine the electric charge
asambeis [7]

Answer:

q = 3.87 x 10⁵ C

Explanation:

given,

Electric field, E = 8.60 x 10¹ = 86 N/C

radius of earth, R = 6371 Km = 6.371 x 10⁶ m

Coulomb constant, K = 9 x 10⁹ N · m²/C²

Charge on the earth = ?

the electric field at the point

E =\dfrac{kq}{r^2}

q =\dfrac{Er^2}{k}

inserting all the values

q =\dfrac{86\times (6.371\times 10^6)^2}{9\times 10^{9}}

      q = 3.87 x 10⁵ C

The electric charge on the earth is equal to 3.87 x 10⁵ C

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All options are wrong here.

The correct answer is..

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