<span>a change in allele frequencies in a population over time also known as evolution</span>
Answer:
static coefficient = 0,203 & kinetic coefficient = 0,14
Explanation:
There are two (2) conditions, when the desk is about to move and when the desk is moving. In the attachements you can see the two free body diagram for each condition.
In the first condition, there is no movement and the force is 12 N, in the image we can see the total forces are equal to 0 and by the definition of the friction force we can get the static friction coefficient.
In the second condition there is movement in the direction of the force which is equal to 8 N, again by the definition of the friction force we can get the kinetic friction coefficient. Since the desk is moving with constant velocity there is not acceleration.
Answer:
v' = 1.5 m/s
Explanation:
given,
mass of the bullet, m = 10 g
initial speed of the bullet, v = 300 m/s
final speed of the bullet after collision, v' = 300/2 = 150 m/s
Mass of the block, M = 1 Kg
initial speed of the block, u = 0 m/s
velocity of the block after collision, u' = ?
using conservation of momentum
m v + Mu = m v' + M u'
0.01 x 300 + 0 = 0.01 x 150 + 1 x v'
v' = 0.01 x 150
v' = 1.5 m/s
Speed of the block after collision is equal to v' = 1.5 m/s
<h2>
Option A is the correct answer.</h2>
Explanation:
Acceleration due to gravity

G = 6.67 × 10⁻¹¹ m² kg⁻¹ s⁻²
Let mass of earth be M and radius of earth be r.
We have

Now
A hypothetical planet has a mass of one-half that of the earth and a radius of twice that of the earth.
Mass of hypothetical planet, M' = M/2
Radius of hypothetical planet, r' = 2r
Substituting

Option A is the correct answer.
Answer:
because it gives a complete thought