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BartSMP [9]
3 years ago
9

What is the average velocity of a bowling ball that moves down the lane 8 meters in 4 seconds?​

Physics
1 answer:
Tema [17]3 years ago
8 0

Answer: 2m/s

Explanation:

V avg = Displacement / time

Displacement is 8

Time is 4

V avg = 2

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The nutritional label above came from a can of soup how many servings of soup would you need to eat to receive your recommended
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Which scenario is an application of Newtons Second Law of Motion?
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The centre of mass of a metre rule is at the 50cm mark. state what is meant by Centre of mass​
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2 years ago
A horizontal 810-N merry-go-round of radius 1.60 m is started from rest by a constant horizontal force of 55 N applied tangentia
Sloan [31]

Answer:

576 joules

Explanation:

From the question we are given the following:

weight = 810 N

radius (r) = 1.6 m

horizontal force (F) = 55 N

time (t) = 4 s

acceleration due to gravity (g) = 9.8 m/s^{2}

K.E = 0.5 x MI x ω^{2}

where MI is the moment of inertia and ω is the angular velocity

MI = 0.5 x m x r^2

mass = weight ÷ g = 810 ÷ 9.8 = 82.65 kg

MI = 0.5 x 82.65 x 1.6^{2}

MI = 105.8 kg.m^{2}

angular velocity (ω) = a x t

angular acceleration (a) = torque ÷ MI

where torque = F x r = 55 x 1.6 = 88 N.m

a= 88 ÷ 105.8 = 0.83 rad /s^{2}

therefore

angular velocity (ω) = a x t = 0.83 x 4 = 3.33 rad/s

K.E = 0.5 x MI x ω^{2}

K.E = 0.5 x 105.8 x 3.33^{2} = 576 joules

6 0
2 years ago
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