Answer:
7.640 kg
Explanation:
Step 1: Write the balanced complete combustion equation for ethanol
C₂H₆O + 3 O₂ ⇒ 2 CO₂ + 3 H₂O
Step 2: Calculate the moles corresponding to 4 kg (4000 g) of C₂H₆O
The molar mass of C₂H₆O is 46.07 g/mol.
4000 g × 1 mol/46.07 g = 86.82 mol
Step 3: Calculate the moles of CO₂ released
86.82 mol C₂H₆O × 2 mol CO₂/1 mol C₂H₆O = 173.6 mol CO₂
Step 4: Calculate the mass corresponding to 173.6 moles of CO₂
The molar mass of CO₂ is 44.01 g/mol.
173.6 mol × 44.01 g/mol = 7640 g = 7.640 kg
The answer is a. concentrated. (If the statement was instead that large amounts of water was involved and smaller amounts of salt, the answer would be instead c. dilute)
Answer:
824 g
Explanation:
First we <u>convert 7.0 x 10²⁴ formula units of magnesium chloride (MgCl₂) into moles</u>, using <em>Avogadro's number</em>:
- 7.0 x 10²⁴ formula units ÷ 6.023x10²³ formula units/mol = 11.62 mol MgCl₂
There are two Cl moles per MgCl₂ moles, meaning that we have (2 * 11.62) 23.24 moles of Cl
Finally we <u>convert 23.24 moles of chlorine into grams</u>, using <em>chlorine's molar mass</em>:
- 23.24 mol * 35.45 g/mol = 824 g
