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Nikolay [14]
4 years ago
5

mark for review (will be highlighted on the review page) 11. a solution that contains a large amount of salt and a small amount

of water is said to be a _______ solution. a. concentrated b. diffused c. dilute d. unsaturated
Chemistry
1 answer:
Naddik [55]4 years ago
6 0
The answer is a. concentrated. (If the statement was instead that large amounts of water was involved and smaller amounts of salt, the answer would be instead c. dilute)
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Nitric acid can be produced by the reaction of gaseous nitrogen dioxide with water. 3 no2(g) + h2o(ℓ) −→ 2 hno3(ℓ) + no(g) if 85
Naya [18.7K]
The balanced equation for the above reaction is as follows;
3NO₂ + H₂O --> 2HNO₃ + NO
stoichiometry of NO₂ to NO is 3:1
molar volume is where 1 mol of any gas occupies a volume of 22.4 L
volume of gas is directly proportional to number of moles of gas.
therefore stoichiometry can be applied for volume as well.
volume ratio of NO₂ to NO is 3:1
volume of NO₂ reacted - 854 L
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volume of NO formed - 285 L
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3 years ago
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What object does a scientist use to measure liters
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Liter measures liquid- so a measuring cup
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Nitrogen gas (112 g) reacts with hydrogen gas to produce 40.8 g of ammonia according to the following
Lemur [1.5K]

Answer:

%yield of NH₃ = 30%

Explanation:

Actual yield of NH₃ = 40.8g

Theoretical yield = ?

Equation of reaction

N₂ + 3H₂ → 2NH₃

Molar mass of NH₃ = 17g/mol

Molarmass of N = 14.00

2 molecules of N = 2 * 14.00 = 28g/mol

Number of moles = mass / molar mass

Mass = number of moles * molar mass

Mass = 1 * 28.00 = 28g of N₂ (the number of moles of N₂ from the equation is 1).

From the equation of reaction,

28g of N₂ produce (2 * 17)g of NH₃

28g of N₂ = 34g of NH₃

112g of N₂ = x g of NH₃

X = (112 * 34) / 28

X = 136g of NH₃

Theoretical yield = 136g of NH₃

% yield = (actual yield / theoretical yield) * 100

% yield = (40.8 / 136) * 100

% yield = 0.3 * 100

% yield = 30%

8 0
3 years ago
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