A buffer is usually composed of either:
- a weak base combined with its conjugate acid, or
- a weak acid combined with its conjugate base
Now, examining each of the choices:
1- KOH and NH3: since they are both bases, thus this mixture is not a buffer
2- HBr and NaCl: since HBr is a strong acid while NaCl is the salt of another different acid, thus this mixture is not a buffer
3- HCl and HBr: these are both considered to be strong acid, thus this mixture is not a buffer
4- HCHO2 and NaCHO2: as for HCH02, it is considered a weak base while NaCHO2 is considered its conjugate base, thus this mixture is a buffer
Answer:
See below.
Explanation:
1. The water here is the solvent, and the 'sugar and fruit specific chemicals' are considered the solute. That is as the solute is the component dissolved in the solvent.
2. The collision theory states that the greater the collisions, the greater the rate of reaction. When powdered sugar is placed in the water (solvent) it occupies more surface area, resulting in more collisions that speed up the rate of reaction, compared to a cube of sugar - that occupies less surface area. Therefore, the powdered sugar dissolved faster.
3. Molarity describes the number of moles of a substance per unit of volume. The standard unit of volume is liter, giving you the standard units (mol/l). Molality describes the number of moles per unit of mass, typically kilograms (mol/kg).
The concentration of a solution can be given in moles of solute dissolved per kilogram of solvent for molality, and moles of solute dissolved in liters of solvent for molarity. Molality is generally used for concentration.
it never will, it will pop
