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3 years ago

9

Leciały kaczki: jedna na przedzie, dwie za nią, jedna z tyłu, dwie przed nią,jedna pomiędzy dwiema i trzy pod rząd. Ile kaczek l

eciało?
Potrzebne na teraz !

1 answer:

balandron [24]3 years ago

7 0

I think its 8, if you count up all the ducks it's 7. But it's talking like it's counting the ducks in front,middle and behind a duck so 7+1=8.

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(-4)^6 (-4)^5 into a single power

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$\huge { - 4}^{11}$

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3 years ago

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3 years ago

The distribution of IQ scores can be modeled by a normal distribution with mean 100 and standard deviation 15.

evablogger [386]

Answer:

4.4% of the population with IQ between 120 and 125.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100

Standard Deviation, σ = 15

We are given that the distribution of IQ scores is a bell shaped distribution that is a normal distribution.

a) Let X be a person's IQ score.

Then, density functions for IQ scores is given by:

$P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{z^2}{2}}\\\\\text{where,}\\\\z = \frac{x-\mu}{\sigma}\\\\P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{(x-\mu)^2}{2\sigma^2}}\\\\P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{(x-100)^2}{450}}$

b) P(population with IQ between 120 and 125.)

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

$P(120 \leq x \leq 125) = P(\displaystyle\frac{120 - 100}{15} \leq z \leq \displaystyle\frac{125-100}{15}) = P(1.33 \leq z \leq 1.66)\\\\= P(z \leq 1.66) - P(z < 1.33)\\= 0.952 - 0.908 = 0.044 = 4.4\%$

$P(120 \leq x \leq 125) = 4.4\%$

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3 years ago

Find the value of k such that the polynomial x2

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Answer:

Step-by-step explanation:

https://www.toppr.com/ask/question/find-the-value-of-k-such-that-the-polynomial-x2k6x22k1/

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3 years ago

If Gabby has 15 cosmetics in a bag, and 5 of those cosmetics are eyeshadow, then what is the probability of her picking an eyesh

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this could be represented in the following way 5/15

Probability is

Fraction= 1/3

Decimal=0.33333333333333

Percentage:33.33333%

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3 years ago

Read 2 more answers