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vladimir1956 [14]
3 years ago
11

What is the common factor in the expression A-2 B-3 C-5 D-10

Mathematics
2 answers:
mamaluj [8]3 years ago
7 0

Answer:

C-5

Step-by-step explanation:

5- 1/5

20-4/5

30-5/6

dusya [7]3 years ago
5 0

Factor 5 out of 5x^2

5(x^2) + 20x + 30

Factor 5 out of 20x

5(x^2) + 5(4x) + 30

Factor 5 out of 30

5x^2 + 5 (4x) + 5 * 6

Factor our of 5x^2 + 5(4x)

5(x^2 + 4x) + 5 * 6

Factor 5 out of 5(x^2 + 4x) + 5 * 6

5(x^2 + 4x + 6)

The GCF = 5

<u>Your answer is: C. 5</u>

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Topic: The Quadratic Formula
Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

x= \frac{-b +- \sqrt{b^2-4ac} }{2a}

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² =  x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\=  -4 or 1

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0
3 years ago
The sum of three consecutive natural numbers is 1251 find the numbers
valentinak56 [21]

Numbers are 416, 417 and 418

<u>Step-by-step explanation:</u>

Step 1:

Let the numbers be x, x + 1 and x + 2. Given that their sum is 1251.

⇒ x  + x + 1 + x + 2 = 1251

⇒ 3x + 3 = 1251

⇒ 3x = 1248

⇒ x = 416

Step 2:

Find the other numbers.

⇒ x + 1 = 417 and x + 2 = 418

8 0
3 years ago
What is the answer to -5x+5y=-10 and 3x-3y=5 using substitution
IceJOKER [234]

Answer:

for the 1st one the answer is x= 3 y=1 and the second one is x= 5 and y = 3 and 1/3

Step-by-step explanation: so basically for the first one -5 times x which is 3 is -15 right? and then 5 times y which is 1 is 5 right so -15 plus 5 = -10

second one is x = 5 and y = 3 and 1/3 because 5*x which is 5 is = to 15 right? and then 3 times y which is equal to 3 and 1/3 is equal to 10 which when you do 15-10 in pretty sure it equals 5 correct me if im wrong

Hope this helps xD ;)

7 0
3 years ago
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