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Nikolay [14]
3 years ago
15

A meter stick whose mass is 260 grams lies on ice. You pull at one end of the meter stick, at right angles to the stick, with a

force 6 newtons. The ensuing motion of the meter stick is quite complicated, but what are the initial magnitude and direction of the rate of change of the momentum of the stick, , when you first apply the force?
Physics
1 answer:
Lelu [443]3 years ago
8 0

Answer:

a = d p / dt = 23 m / s²,   The direction is the direction of the force

Explanation:

Newton's second law can be written in the form

             F = dp / dt

How the body is initially at rest

           F = m a

           a = F /m

           a = 6 /0.260

           a = 23 m / s²

           a = d p / dt = 23 m / s²

The direction is the direction of the force

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Pigments that ABSORB all colors look _____.<br> Pigment that REFLECT all colors look _____.
Basile [38]
Yo I wish I was at higheschool and I think the last one is darker or the same cause of the reflection
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3 years ago
You spy on an anchor on the bottom of a lake. What is the direction and amount of force the water exerts on it: a) zero
vaieri [72.5K]

Answer:

c) up, less than the weight of the anchor

Explanation:

An object floats when the weight of the water the object displaces is equal to the weight of the object. In this case the weight of the anchor and the weight of the water it displaces is not the same so it sinks. Buoyancy is the force that acts on body when it is in water.

When buoyancy is less than the force that the object is generating due to gravity the object sinks. Buoyancy always acts up.

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3 years ago
If the 78.0 kg astronaut were in a spacecraft 6R from the center of the earth, what would the astronaut's weight be on earth? 76
den301095 [7]

(a) 764.4 N

The weight of the astronaut on Earth is given by:

F=mg

where

m is the astronaut's mass

g is the acceleration due to gravity

Here we have

m = 78.0 kg

g = 9.8 m/s^2 at the Earth's surface

So the weight of the astronaut is

F=(78.0)(9.8)=764.4 N

(b) 21.1 N

The spacecraft is located at a distance of

r=6R

from the center of Earth.

The acceleration due to gravity at a generic distance r from the Earth's center is

g=\frac{GM}{r^2}

where G is the gravitational constant and M is the Earth's mass.

We know that at a distance of r = R (at the Earth's surface) the value of g is 9.8 m/s^2, so we can write:

GM=9.8R^2 (1)

the acceleration due to gravity at r=6R instead will be

g'=\frac{GM}{(6R)^2}

And substituting (1) into this formula,

g'=\frac{9.8R^2}{36R^2}=0.27 m/s^2

So the weight of the astronaut at the spacecratf location is

F'=mg'=(78.0 kg)(0.27 m/s^2)=21.1 N

6 0
4 years ago
The cheetah can reach a top speed of 114 km/h (71 mi/h). While chasing its prey in a short sprint, a cheetah starts from rest an
Mariulka [41]

Answer: a= 4.4ms-2

Displacement= 26.95 m

Explanation:

First, the speed in km/hr must be converted to m/s so that we can apply it in solving the question. The motion started from rest hence the initial velocity is 0m/s. The average displacement is also obtained from the equations of motion as shown in the image attached.

7 0
4 years ago
Read 2 more answers
Consider two diffraction gratings with the same slit separation. The only difference between the two gratings is that one gratin
kobusy [5.1K]

Answer:

True The grid with more slits gives more angle separation increases

True. The grating with 10 slits produces better-defined (narrower) peaks

Explanation:

Such a system can be seen as a diffraction network in this case with different number of lines per unit length, the expression for the constructive interference of a diffraction network is

      d sin θ = m λ

where d is the distance between slits or lines, m the order of diffraction and λ the wavelength.

For network with 5 slits

      d = 1/5 = 0.2

For the network with 10 slits

      d = 1/10 = 0.1

let's calculate the separation (teat) for each one

      θ = sin⁻¹ (m λ / d)

for 5 slits

     θ₅ = sin⁻¹ (m λ 5)

for 10 slits

     θ₁₀ = sin⁻¹ (m λ 10)

we can appreciate that for more slits the angle increases

the intensity of a series of slits is

       I = I₀ sin²2 (N d/2) / sin² d/2)

when there are more slits (N) the peaks have greater intensity and are more acute (half width decreases)

let's analyze the claims

False

True The grid with more slits gives more angle separation increases

False

True The expression for the intensity of the diffraction peaks the intensity of the peaks increases with the number of slits as well as their spectral width decreases

False

5 0
4 years ago
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