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olganol [36]
3 years ago
13

How much force is needed to accelerate a 500.0 kg car at a rate of 4 m/s2?

Physics
1 answer:
il63 [147K]3 years ago
3 0

Answer:2000 N =2kN

             

Explanation:

F=m*a

m=500kg

a=4m/s²

F=500kg*4m/s²

F=2000N

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Any projectile always has a constant vertical acceleration of _______.
Mashcka [7]

Answer:

The answer to your question is: C. -9.81 m/s²

Explanation:

A. 9.81 m/s²  acceleration is considered positive when it goes to the center of the earth, so this option is incorrect.

B. 0 m/s²  This option is incorrect because acceleration is 0 for a linear motion without acceleration.

C. -9.81 m/s²  If a projectile goes to the sky, then the acceleration will be negative.

D. It is not constant. Acceleration is constant.

8 0
3 years ago
Marcy pulls a backpack on wheels down the 100 m hall. The 60N force is applied at an angle of 30° above the horizontal. How much
shutvik [7]

Work= Fcos∆×S

W=60N×cos 30⁰×100

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6 0
3 years ago
You have a sealed glass jar full of air. If you put it in the freezer, what happens to the gas pressure in the jar?
xz_007 [3.2K]
The pressure inside decreases
8 0
3 years ago
A 31.7 kg kid initially at rest slides down a frictionless water slide at 53.2 degrees, how fast is she moving in 3.45 s later?
Murrr4er [49]

Answer:

34.55 m/s

Explanation:

8 0
3 years ago
How much work does this force do as the particle moves along the x-axis from x = 0 to x = l? express your answer in terms of the
nydimaria [60]
<h3><u>Answer</u>;</h3>

= F0 L ( 1 - 1/e )

<h3><u>Explanation;</u></h3>

Work done is given as the product of force and distance.

In this case;

Work done  = ∫︎ F(x) dx  

                    = F0 ∫︎ e^(-x/L) dx  

                    = F0 [ -L e^(-x/L) ] between 0 and L  

                    = F0 L ( 1 - 1/e )

3 0
4 years ago
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