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olganol [36]
3 years ago
13

How much force is needed to accelerate a 500.0 kg car at a rate of 4 m/s2?

Physics
1 answer:
il63 [147K]3 years ago
3 0

Answer:2000 N =2kN

             

Explanation:

F=m*a

m=500kg

a=4m/s²

F=500kg*4m/s²

F=2000N

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madam [21]

Hi there!

We can use the kinematic equation:

v_f^2 = v_i^2 + 2ad

vf = Final velocity (? m/s)

vi = initial velocity (0 m/s, dropped from rest)

a = acceleration (due to gravity, 9.8 m/s²)

d = distance (9.8 m)

Simplify the equation to solve for vf:

v_f^2 = 0 + 2ad\\\\v_f = \sqrt{2ad}

Substitute in the given values:

v_f = \sqrt{2(9.8)(9.8)} = \boxed{13.86 m/s}

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Please can someone help?
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5207 because I said so
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Which is denser?<br><br> The water in a swimming pool or a quarter (coin).
PolarNik [594]

Answer:

The coin is denser than any of the liquids, and will sink through everything. The oil is the least dense liquid, so it will float on the water, and the syrup is the densest liquid, so it will sink below the water.

Explanation:

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4 0
3 years ago
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wolverine [178]

Answer:

a. The acceleration of the bowling ball is 9.5 m/s² toward the center

b.  The tension in the rope is 140.24 N

Explanation:

given information:

ball weight,  W = 71.2 N

the length of rope, R = 3.30 m

ball speed, v = 5.60 m/s

a. The acceleration of the bowling ball, α

α = \frac{v^{2} }{R}

where

α = the acceleration

v = the speed

R = radius

thus

α = \frac{v^{2} }{R}

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b. The tension in the rope?

according to the Newton's second law

ΣF = m a

where

F = force

m = mass

a = acceleration

so,

ΣF = m a

T - W = m a

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<u>Explanation</u>:

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3 0
2 years ago
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