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Liula [17]
3 years ago
15

Use the position equation given below, where s represents the height of the object (in feet), v0 represents the initial velocity

of the object (in feet per second), s0 represents the initial height of the object (in feet), and t represents the time (in seconds), as the model for the problem.
s = –16t2 + v0t + s0
You drop a coin from the top of a building. The building has a height of 942 feet.
(a) Use the position equation to write a mathematical model for the height of the coin.
s=__________

(b) Find the height of the coin after 4 seconds.
s = _______ ft

(c) How long will it take before the coin strikes the ground? (Round your answer to two decimal places.)
t = _______ sec
Physics
1 answer:
mixer [17]3 years ago
6 0
Yes i think so!!!
i think..
your totally right Angi. 
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A 65 N boy sits on a sled weighing 52 N on a horizontal surface. The coefficient of friction between the sled and the snow is 0.
pogonyaev

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1.40 N

Explanation:

The magnitude of the frictional force is given by:

F=\mu N

where

\mu is the coefficient of friction

N is the magnitude of the normal reaction

The coefficient of friction for this problem is \mu=0.012. The magnitude of the normal reaction is equal to the combined weight of the boy and the sled, because the surface is horizontal, so

N=65 N+52 N=117 N

Therefore, the frictional force is

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3 0
3 years ago
The altitude of a hang glider is increasing at a rate of 6.75 m/s. At the same time, the shadow of the glider moves along the gr
Rufina [12.5K]

Answer:

16.45 m/s

Explanation:

Let y be the vertical distance and x be the horizontal distance

We are given that

The altitude of hang glider increasing at the rate=v_y=\frac{dy}{dt}==6.75m/s

The shadow of the glider moves along the ground at speed=v_x=\frac{dx}{dt}=15m/s

We have to find the magnitude of glider's velocity.

We know that

Magnitude of velocity=v=\sqrt{v^2_x+v^2_y}

Substitute the values

v=\sqrt{(15)^2+(6.75)^2}

v=\sqrt{225+45.5625}

v=16.45m/s

Hence, the magnitude of glider's velocity=16.45 m/s

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