Answer:
The planet search technique currently best suited to find Earth-like planets is gravitational microlensing.
Explanation:
<u><em>Gravitational microlensing</em></u>
When a foreground star (lensing star) passes in front of a background star (source star), due to its gravitational field it warps space and magnifies the light coming from the source star. If the lensing star has a planet orbiting near, the planet's gravity also bends light and intensifies this effect. What is observed is a sharp increase in brightness in the otherwise regular pattern of the microlensing event. Certain characteristics of the planet like its total mass, orbit and period can be obtained from said pattern.
This technique is independent of the wavelength of the source star which makes it suitable for any kind of electromagnetic radiation.
Microlensing is suitable to find smaller, rocky planets like Earth because is more sensitive to planets whose orbits are further apart from the parent star.
Other indirect detection techniques like the radial velocity method and the transit method are biased towards massive gaseous planets that orbit very close to their parent star.
- The <em>radial velocity method</em> makes use of the Doppler effect, that involves the change in frequency of a wave depending on the relative movement of the observer and the wave source. This relative motion, that should be in the line that joins the wave source and the observer, is called the radial motion. That is why the velocity of this motion is called the radial velocity. If a star is moving towards Earth the light waves reach us faster. We say the spectrum is blue shifted because the color blue has the shortest wavelength in the visible spectrum. If the star is moving away from the Earth the light waves reach us later and the wavelength becomes larger. We say the spectrum is red shifted because the color red has the longest wavelength. If a planet is orbiting star there will be stellar motion caused by the tug of the planet, the doppler shift allow us to detect this subtle motion. Is currently unsuitable to detect small, rocky planets like Earth because maasive planets orbiting very close to their stars create a larger and easily to note spectral shift.
- <em>Transit method </em>: if a planet crosses in front of the star it orbits, the star brightness tenporarily decreases a little. This method is also unsuitable because with large and gaseous planets the drop in brightness iseasier to spot.
Complete Question
Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approximately 57.0 m . If the track is completely flat and the race car is traveling at a constant 30.5 m/s (about 68 mph ) around the turn.
Required:
a. What is the race car's centripetal (radial) acceleration?
b. What is the force responsible for the centripetal acceleration in this case?
O normal
O gravity
O friction
O weight
Answer:
question a
question b
correct option is option 3
Explanation:
From the question we are told that
The radius is 
The constant speed at which the race car is travelling is 
Generally from the question we are told that the track is completely flat so the only force pulling the car to the middle is the frictional force hence the centripetal force is due to the frictional force
Generally the centripetal acceleration is mathematically represented as
=> 
=>
Answer:
436.56 centimeters
Explanation:
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