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Pani-rosa [81]
2 years ago
14

You spy on an anchor on the bottom of a lake. What is the direction and amount of force the water exerts on it: a) zero

Physics
1 answer:
vaieri [72.5K]2 years ago
5 0

Answer:

c) up, less than the weight of the anchor

Explanation:

An object floats when the weight of the water the object displaces is equal to the weight of the object. In this case the weight of the anchor and the weight of the water it displaces is not the same so it sinks. Buoyancy is the force that acts on body when it is in water.

When buoyancy is less than the force that the object is generating due to gravity the object sinks. Buoyancy always acts up.

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The ice cap at the North Pole may be 1000 m thick, with a density of 920 kg/m3. Find the pressure at the bottom and the correspo
bija089 [108]
<span>Pice=920kg/m^3 deltaP=PgH=920kg/m^3 X 9.80665m/s^2 X 1000m = 9022118 Pa P=Po + deltaP=101.325 + 9022 = 9123kPa</span>
7 0
2 years ago
A force of 1.35 newtons is required to accelerate a book by 1.5 meters/second2 along a frictionless surface. What is the mass of
malfutka [58]

B. seems like the answer, I'm not sure.

3 0
3 years ago
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Choose all the answers that apply.
spin [16.1K]

Answer:

B and C?

Explanation:

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2 years ago
On a flat surface, a moving bicycle has _____ energy than a stationary car. A. less kinetic B. more kinetic C. less potential D.
Marina86 [1]
On a flat surface a moving bicycle has more kinetic energy than a stationary car
3 0
3 years ago
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A tube 1.20 m long is closed at one end. A stretched wire is placed near the open end. The wire is 0.350 m long and has a mass o
Ksju [112]

Answer:

71.4583 Hz

67.9064 N

Explanation:

L = Length of tube = 1.2 m

l = Length of wire = 0.35 m

m = Mass of wire = 9.5 g

v = Speed of sound in air = 343 m/s

The fundamental frequency of the tube (closed at one end) is given by

f=\frac{v}{4L}\\\Rightarrow f=\frac{343}{4\times 1.2}\\\Rightarrow f=71.4583\ Hz

The fundamental frequency of the wire and tube is equal so he fundamental frequency of the wire is 71.4583 Hz

The linear density of the wire is

\mu=\frac{m}{l}\\\Rightarrow \mu=\frac{9.5\times 10^{-3}}{0.35}\\\Rightarrow \mu=0.02714\ kg/m

The fundamental frequency of the wire is given by

f=\frac{1}{2l}\sqrt{\frac{T}{\mu}}\\\Rightarrow f^2=\frac{1}{4l^2}\frac{T}{\mu}\\\Rightarrow T=f^2\mu 4l^2\\\Rightarrow T=71.4583^2\times 0.02714\times 4\times 0.35^2\\\Rightarrow T=67.9064\ N

The tension in the wire is 67.9064 N

7 0
2 years ago
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