Recall the secant-tangent theorem, and you have
EA^2 = EC*CD
12^2 = 8*(x+10)
and now ED = EC+CD = 8+x+10
I suspect a typo somewhere in the murk above
Answer:
I don't know
Step-by-step explanation:
How you will find out the value of 'n ' ?
[ n! × 2^( n-4 ) / { 4! × ( n-4 )! } ] = [ n! × 2^( n-5 ) / { 5! × ( n-5 )! } ]
Answer:
50
Step-by-step explanation:
since the Pythagorean theorem is
√
b is the bottom line (48)
a is the right line (14)
c is the top line (c)
plug that in
√
then do the exponets
= 14 * 14 = 196
= 48 * 48 = 2304
then add them together
196 + 2304 = 2500
√2500
the sqrt of 2500 is 50 (50 * 50 = 2500)
c = 50
your answer is 50
hope this helps:)