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Marrrta [24]
3 years ago
5

1. Jillian Knits hats for her family and friends. In the week, she knits 4 hats, the next week, she has some help and together,

they knit four times as the week before. The fourth week Jillian her friends and family knit four times as many hats as the third week. How many hats will they knit on the fourth week? (ANSWERS: A• 16 Hats B•32 C•64 D•256) 2. is there an error writing 5 x 5 as 3/5 if so, what is it? (ANSWERS: A• There is no error because 5 x 5 x 5 = 3/5 B• There is no error because 5 x 5 x 5 = 5/15 C• There is no error because 5 x 5 x 5 = 25/2 D• There is no error because 5 x 5 x 5 = 5/3 3. )Apply the order of operations to simplify each expressions. 2/4 - 8 x 2 divide 4= ___ ( ANSWERS: A• 0 B• 12 C• 16 D• 4 ) Please help and thanks :)

Mathematics
1 answer:
alexandr1967 [171]3 years ago
7 0

Question 1: If shes making 4 hats alone and then Quadruples it shes making 16 hats per week if she quadruples it again she will be knitting 64 hats per week.

4x4=16

16x4=64hats

Question 2: There is an error because 5x5x5 = 5³

Question 3: 2⁴ - 8 x 2 / 4 = 12

2⁴ = 16  - 8 x 2 / 4

8x2 = 16

16/4 = 4

16-4 = 12

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A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
AURORKA [14]

Answer:

(−0.103371 ; 0.063371) ;

No ;

( -0.0463642, 0.0063642)

Step-by-step explanation:

Shift 1:

Sample size, n1 = 30

Mean, m1 = 10.53 mm ; Standard deviation, s1 = 0.14mm

Shift 2:

Sample size, n2 = 25

Mean, m2 = 10.55 ; Standard deviation, s2 = 0.17

Mean difference ; μ1 - μ2

Zcritical at 95% confidence interval = 1.96

Using the relation :

(m1 - m2) ± Zcritical * (s1²/n1 + s2²/n2)

(10.53-10.55) ± 1.96*sqrt(0.14^2/30 + 0.17^2/25)

Lower boundary :

-0.02 - 0.0833710 = −0.103371

Upper boundary :

-0.02 + 0.0833710 = 0.063371

(−0.103371 ; 0.063371)

B.)

We cannot conclude that gasket from shift 2 are on average wider Than gasket from shift 1, since the interval contains 0.

C.)

For sample size :

n1 = 300 ; n2 = 250

(10.53-10.55) ± 1.96*sqrt(0.14^2/300 + 0.17^2/250)

Lower boundary :

-0.02 - 0.0263642 = −0.0463642

Upper boundary :

-0.02 + 0.0263642 = 0.0063642

( -0.0463642, 0.0063642)

7 0
3 years ago
Roselyn wants to drive her car at a speed of 606060 miles per hour for 1.251.251, point, 25 hours. Her car has a fuel efficiency
inessss [21]

Answer:

Hence, there is 5 gallons of fuel Roselyn needed for her journey.

Step-by-step explanation:

Since we have given that

Speed at which Roselyn wants to drive her car = 60 miles per hour

Time taken by her car = 1.5 hours

As we know the formula for "Distance-Speed " :

Her car has fuel efficiency = 15 miles per gallon

Number of gallons of fuel is given by

Read more on Brainly.com - brainly.com/question/2059692#readmore

8 0
3 years ago
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If you have a set of alternate exterior angles on parallel lines, then the measure will be equal
Luba_88 [7]
Always.
So it is B.
Hope This Helps
5 0
3 years ago
In two or more complete sentences describe why the following series is an example of an infinite series.
Svetlanka [38]

Answer:


Step-by-step explanation:

There are an infinite number of these whole numbers. Thus the series goes on without bounds. Whatever very big number you can think of there is another one which is 1 greater.

4 0
3 years ago
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Can anybody help me on this please I will be giving 15 points..
oksano4ka [1.4K]

Answer:

BC=\sqrt{95}

Angle A (or BAC)=54.31466...

Angle C (or ACB)=35.68533...

Step-by-step explanation:

\frac{7}{\sin \left(\angle \:ACB\right)}=\frac{12}{\sin \left(90\right)}

BC=\sqrt{12^2-7^2}

\sqrt{12^2-7^2}=\sqrt{95}

\frac{\sqrt{95}}{\sin \left(\angle \:BAC\right)}=\frac{12}{\sin \left(90\right)}\quad :\quad \angle \:BAC=54.31466

\frac{7}{\sin \left(\angle \:ACB\right)}=\frac{12}{\sin \left(90\right)}\quad :\quad \angle \:ACB=35.68533

4 0
3 years ago
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