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3 years ago

A person riding north on a bicycle speeds up from 0 m/s to 9 m/s in 3 seconds. The acceleration of the bicycle is m/s2.

Physics

2 answers:

MariettaO [177]3 years ago

4 0

Answer:

Explanation:

on edg

Elis [28]3 years ago

3 0

Answer:

3 m/s^2

Explanation:

Time: 3 sec

Initial velocity: 0m/s

Final velocity: 9 m/s

Formula for acceleration:

a = <u>Vf - Vi</u>

a = <u>9 - 0</u>

a = 9/3

a = 3 m/s^2

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a 550 kg car accelerates from 15 m/s to 25 m/s in 15 s by applying a constant force. how large of a force is exerted? Please sho

Novay_Z [31]

You'll be using the equation f = m a, or force = mass x acceleration

First, you have to find the acceleration. The acceleration needed is the average acceleration over the 15 seconds is accelerated. So, you take the change in speed (25m/s - 15m/s) to get a change of 10m/s.
The average acceleration (acceleration per second) is found by dividing total acceleration by the time it took. So, it's 10 / 15, which equals .6. This is a, your acceleration
Now just plug it into the equation F = m a, because it already gives you the mass of the car
F = 550 x .6
Solve that to get F = 366.6. F is measured in Newtons (N), so your answer is 366.6N

3 0

3 years ago

At 5.0 minutes, the temperature of the water reaches 100 °C. The volume of the water in the urn

serious [3.7K]

Answer:

fdvevddvevkejokef0jeovdlvkjeuiyv

Explanation:

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4 0

3 years ago

at certain times the demand for electric energy is low and electric energy is used to pump water to a reservoir 45 m above the g

Readme [11.4K]

The mass of water that must be raised is $5.25\cdot 10^7 kg$

Explanation:

Since the process is 70% efficiency, the power in output to the turbine can be written as

$P_{out} = 0.70 P_{in}$

where $P_{in}$ is the power in input.

The power in input can be written as

$P_{in} = \frac{W}{t}$

where

W is the work done in lifting the water

t = 3 h = 10,800 s is the time elapsed

The work done in lifting the water is given by

$W=mgh$

where

m is the mass of water

$g=9.8 m/s^2$ is the acceleration of gravity

h = 45 m is the height at which the water is lifted

Combining the three equations together, we get:

$P_{out} = 0.70 \frac{mgh}{t}$

Where

$P_{out} = 150 MW = 150\cdot 10^6 W$

And solving for m, we find:

$m=\frac{Pt}{0.70gh}=\frac{(1.50\cdot 10^6)(10800)}{(0.70)(9.8)(45)}=5.25\cdot 10^7 kg$

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

3 0

4 years ago

The average intensity of light emerging from a polarizing sheet is 0.775 W/m2, and that of the horizontally polarized light inci

rewona [7]

Answer:

the transmission axis of polarizing sheet makes an angle of $\Theta =26.74^{\circ}$ with the horizontal

Explanation:

We have given that intensity of light incident on the sheet $I_0=0.970W/m^2$

Average intensity of light emerging from a polarizing sheet $I=0.775W/m^2$

We have to find the angle between transmission axis with the horizontal

Intensity of light polarizing from sheet is equal to $I=I_0cos^2\Theta$

So $0.775=0.970cos^2\Theta$

$cos^2\Theta =0.798$

$cos\Theta =0.893$

$\Theta =26.74^{\circ}$

So the transmission axis of polarizing sheet makes an angle of $\Theta =26.74^{\circ}$ with the horizontal

5 0

3 years ago

A lawn sprinkler sprays water 8 feet at full pressure as it rotates 360 degrees. if the water pressure is reduced by 50%, what i

lina2011 [118]

The area of the sprinkles can be determined through the area of a circle that is pi * r^2 in which the given dimensions above are the radii, r. The second scenarios radius is only half of the original, that is 4 ft. In this case, we can compute the area of the second again. We calculate next the difference of two areas of circles.

7 0

4 years ago