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3 years ago

11

Which term describes an image that is in the opposite orientation than the object from which it was formed? virtual erect invert

ed lateral

1 answer:

DiKsa [7]3 years ago

7 0

Answer:

lateral

...............

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In 1929, American astronomer Edwin Hubble discovered that distant galaxies were moving away from us. He found that light from di

Novay_Z [31]

Answer:

it is the Hubble law

Explanation:

Hubble's law, also known as the Hubble–Lemaître law, is the observation in physical cosmology that galaxies are moving away from the Earth at speeds proportional to their distance. In other words, the farther they are the faster they are moving away from Earth.

7 0

3 years ago

Read 2 more answers

A spaceship from a friendly, extragalactic planet flies toward Earth at 0.201 times the speed of light and shines a powerful las

bagirrra123 [75]

Answer:

The wavelength of observed light on earth is 568.5 nm

Explanation:

Given that,

Velocity of spaceship $v= 0.201c$

Wavelength of laser $\lambda= 697\ nm$

We need to calculate the wavelength of observed light on earth

Using formula of wavelength

$\lambda_{0}=\lambda_{e}\times\sqrt{\dfrac{1-\dfrac{v}{c}}{1+\dfrac{v}{c}}}$

$\lambda_{0}=697\times10^{-9}\times\sqrt{\dfrac{1-\dfrac{0.201 c}{c}}{1+\dfrac{0.201c}{c}}}$

$\lambda_{0}=697\times10^{-9}\times\sqrt{\dfrac{1-0.201}{1+0.201}}$

$\lambda=5.685\times10^{-7}\ m$

$\lambda=568.5\times10^{-9}\ m$

$\lambda=568.5\ nm$

Hence, The wavelength of observed light on earth is 568.5 nm

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4 years ago

Which statement is true about the type of light used by plants to make sugar during photosynthesis? Group of answer choices

denis-greek [22]

Answer:

4. It is infrared.

Explanation:

the photosystems on the chlorophyll absorb light at 600-700nm

3 0

3 years ago

Plz do it all i will give brainlest and thanks to best answer do it right plz

kirill115 [55]

The answer is D

Explanation:

soundwaves can travel through water aka a liquid but secondary waves cant

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3 years ago

find the coefficient of kinetic friction for a 10 kg box being dragged steadily across the surface with a force of 2.0 Newtons

Mazyrski [523]

Answer:

0.02

Explanation:

Force, $F=\mu_k N$ where N is normal reaction and coefficient of kinetic friction is $\mu_k$ . Also, N is equivalent to mg ie N=mg where m is mass of an object and g is acceleration due to gravity. Making $\mu$ the subject of the formula then

$\mu_k=\frac {F}{mg}$

Substituting F with 2 N, m with 10 kg and g with 9.81 then

$\mu_k=\frac {2}{10\times 9.81}=0.0203873598369\approx 0.02$

5 0

4 years ago