All categories

2 years ago

__________ involves determining what qualities are to beused to perform project activities.

Computers and Technology

1 answer:

Alex_Xolod [135]2 years ago

4 0

Answer:

Cost Budgeting

Explanation:

Great question, it is always good to ask away and get rid of any doubts that you may be having.

The answer to this question is Cost Budgeting the keyword in the sentence that verifies this is "qualities". Cost Budgeting is the process of determining were to spend less money or more money, based on importance. In other words determining the which quality of product is better for the overall project activity.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

You might be interested in

Who conceptualizes the design and the working of a website

Citrus2011 [14]

Answer is "Web Designer".

Web Designers are the "artists" of the website. They conceptualize the layout and functionality of the site, from features to format. They may do little coding, and are mostly involved in the creative elements of web design. The Web Developer is less big-picture, and more knitty-gritty building of the website. She is the one who does the coding and actually builds the website, using the web designer's model.

3 0

3 years ago

Consider two different implementations, M1 and M2, of the same instruction set. There are three classes of instructions (A, B, a

Margaret [11]

Explanation:

A.)

we have two machines M1 and M2

cpi stands for clocks per instruction.

to get cpi for machine 1:

= we multiply frequencies with their corresponding M1 cycles and add everything up

50/100 x 1 = 0.5

20/100 x 2 = 0.4

30/100 x 3 = 0.9

CPI for M1 = 0.5 + 0.4 + 0.9 = 1.8

We find CPI for machine 2

we use the same formula we used for 1 above

50/100 x 2 = 1

20/100 x 3 = 0.6

30/100 x 4 = 1.2

CPI for m2 = 1 + 0.6 + 1.2 = 2.8

B.)

CPU execution time for m1 and m2

this is calculated by using the formula;

I * CPI/clock cycle time

execution time for A:

= I * 1.8/60X10⁶

= I x 30 nsec

execution time b:

I x 2.8/80x10⁶

= I x 35 nsec

6 0

2 years ago

To plan a pizza party, one may want to order enough pizza for everyone. Use the slicesPerPizza, slicesPerGuest, and totalGuests

attashe74 [19]

Answer:

import java.util.Scanner;

public class num6 {

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

System.out.println("Enter number of guest");

int totalGuest = in.nextInt();

System.out.println("Enter number of slices per guest");

int slicesPerGuest = in.nextInt();

System.out.println("How many Slices are on a pizza");

int slicesPerPizza = in.nextInt(); // Assume each pizza has 5 slices

double pizzasNeeded;

//Calculating the pizza Needed

int totalslicesNeeded = totalGuest * slicesPerGuest;

pizzasNeeded = totalslicesNeeded/slicesPerPizza;

System.out.println(pizzasNeeded);

}

Explanation:

In this program User is required to enter values for the variables totalGuest, slicesPerGuest and slicesPerPizza

First calculate the totalSlices needed by totalGuest * slicesPerGuest;

The calculate number of pizzas needed by totalslicesNeeded/slicesPerPizza;

4 0

2 years ago

The basic form of backup used in magnetic tape operations is called

Harrizon [31]

Answer is the son-father-grandfather concept. Good luck

5 0

2 years ago

Write a function (named n_pointed_star) to make the turtle draw an n-pointed star. The function should return nothing, and accep

Andreyy89

Answer:

import sys

import turtle

import random

def n_pointed_star(total_points):

if total_points <= 4:

raise ValueError('Not enough total_points')

area = 150

for coprime in range(total_points//2, 1, -1):

if greatest_common_divisor(total_points, coprime) == 1:

start = turtle.position()

for _ in range(total_points):

turtle.forward(area)

turtle.left(360.0 / total_points * coprime)

turtle.setposition(start)

return

def greatest_common_divisor(a, b):

while b != 0:

a, b = b, a % b

return a

turtle.reset()

n_pointed_star(5)

Explanation:

Inside the n_pointed_star function, check whether the total no. of points are less than or equal to 4 and then throw an exception.
Loop through the total_points variable and check whether the result from greatest_common_divisor is equal to 1 or not and then set the starting position of turtle and move it.
Create the greatest_common_divisor which takes two parameters a and b to find the GCD.
Finally reset the turtle and call the n_pointed_star function.

8 0

3 years ago