Answer:
about 19 or 20 g
Explanation:
To do this, is neccesary to watch a solubility curve of this compound. This is the only way that you can know how many grams are neccesary to dissolve this compound in 50 mL of water to a given temperature.
Now, if you watched the attached graph, you can see the solubility curve of many compounds in 100 g of water (or 100 mL of water). So, to know how many do you need in 50 mL, it's just the half.
So watching the curve, you can see that at 20 °C, we simply need between 35 g and 40 g. Let's just say we need 38 grams of NH4Cl to be dissolved in 100 mL of water.
So, in 50 mL, it's just the half. So, we only need 19 g or 20 g of NH4Cl at 20 °C, to dissolve this compound in water.
For the answer to the question above, "35S has more neutrons than 32S; Hershey and Chase used it because it is radioactive and can be easily traced" is the way <span>this isotope differ from the 32S isotope found in greatest natural abundance and this is why they chose 35S instead of 32S.</span>
It would be C) the dark colored peppered moths.
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Answer: The concentration of lead nitrate Pb(NO3)2 in a 0.726 M solution is 0.755 molal.
Explanation:
<u>Given:</u>
The molar mass of Pb(NO3)2 is <u>331.2 g/mol</u>
Assuming 1 litre of solution. This would equal <u>1202 g</u> of solution
In the one litre of solution, you have 0.726 mol Pb(NO3)2
0.726 mol (331.2 g/mol) = 240.5 g Pb(NO3)2
Mass of water in 1 L of solution = 1202 g - 240.5 g = 961.5 g = 0.9615 kg
Molality = mols of solute / kg of solvent
= 0.726 mol / 0.9615 kg
= 0.755 <em>m</em> Pb(NO3)2
Answer:
The number of moles of SO₃ produced by SO₂ are less so it is limiting reactant.
Explanation:
Given data:
Number of moles of SO₂ = 3.1 mol
Number of moles of O₂ = 2.7 mol
Limiting reactant = ?
Solution:
Chemical equation;
2SO₂ + O₂ → 2SO₃
Now we will compare the moles of SO₃ with O₂ and SO₂.
SO₂ : SO₃
2 : 2
3.1 : 3.1
O₂ : SO₃
1 : 2
2.7 : 2×2.7 = 5.4 mol
The number of moles of SO₃ produced by SO₂ are less so it is limiting reactant.
