Analytical chemistry studies and uses instruments and methods used to separate, identify, and quantify matter
Answer:
this is too easy just do it yourself
<h3>Further explanation</h3>
Given
Reaction
H₂ (g) + I₂ (g) → 2HI(g)
Required
The equilibrium constant
Solution
The equilibrium constant is the value of the product in the equilibrium state of the substance in the right (product) divided by the substance in the left (reactant) with the exponents of each reaction coefficient
The equilibrium constant for reaction
pA + qB ⇒ mC + nD
![\large {\boxed {\bold {K ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7BK%20~%20%3D%20~%20%5Cfrac%20%7B%5BC%5D%20%5E%20m%20%5BD%5D%20%5E%20n%7D%20%7B%5BA%5D%20%5E%20p%20%5BB%5D%20%5E%20q%7D%7D%7D%7D)
So for the above reaction :
![\tt K=\dfrac{[HI]^2}{[H_2][I_2]}](https://tex.z-dn.net/?f=%5Ctt%20K%3D%5Cdfrac%7B%5BHI%5D%5E2%7D%7B%5BH_2%5D%5BI_2%5D%7D)
Answer:
Explanation:
Half life of Nobelium-253 is 97 seconds . That means after every 97 seconds half of the Nobelium amount will be disintegrated .
Time taken in bringing the sample to laboratory = 291 seconds
291 second = 291 / 97 half life
n = 3
N = 
N₀ is original mass , N is mass after n number of half life.
N = 5 mg x 
= .625 mg
Only 0.625 mg of Nobelium-253 will be left .
Answer:
2.34g of NaCl
Explanation:
HCl(aq) + NaOH(aq) --------> NaCl(aq) + H2O(l)
Number of moles of HCl= 8 × 5/1000= 0.04 moles
Number of moles of NaOH= 2.4 × 20/1000= 0.048 moles
HCl is the limiting reactant
From the balanced reaction equation, 1 mole of HCl produced 58.5g of NaCl
0.04 moles of HCl will produce 0.04 × 58.5 = 2.34g of NaCl