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gayaneshka [121]
3 years ago
6

If an element is in period 5 what do we know about the electron configuration?

Chemistry
1 answer:
Lynna [10]3 years ago
7 0

Answer: Number of energy shells

Explanation:

Periods = no. of shells

Groups = no. of electrons in outer shells

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The elements on the periodic table that are light blue are:
AlekseyPX

Answer: I think it is noble gasses.

Explanation: Use the website Dynamic Periodic Table for stuff like that it helps.

8 0
3 years ago
There are ________ σ bonds and ________ π bonds in h3c-ch2-ch=ch-ch2-c≡ch.
FrozenT [24]
The number of sigma and pi bonds are,

          Sigma Bonds  =  16

          Pi Bonds         =   3

Explanation:
                   Every first bond formed between two atoms is sigma. Pi bond is formed when already a sigma bond is there. While in case of Alkyne (triple Bond) there is one sigma and one pi bond already present, so the third bond is formed by second side-to-side overlap of orbitals, hence, a second pi bond is formed.
Below all black bonds are sigma bonds, while in alkene there is one pi bond and in alkyne there are two pi bonds.

6 0
3 years ago
Agree or disagree? Explain (2 ideas, 2 examples)
yawa3891 [41]

Answer:

Agree this is correct if it not blame me

6 0
3 years ago
Which statement best describes the properties of sucrose?
crimeas [40]

Answer:

D. They are different from the properties of carbon, oxygen, and hydrogen.  

Step-by-step explanation:

Carbon, oxygen, and hydrogen are all <em>elements. </em>

Sucrose is a <em>compound</em> containing carbon, oxygen, and hydrogen. Its properties are different from those of its elements.

For example, carbon is a <em>black solid,</em> while oxygen and hydrogen are <em>colourless gases</em>. Sucrose is a <em>white solid</em>.

6 0
3 years ago
Read 2 more answers
Ethyl butyrate, CH3CH2CH2CO2CH2CH3, is an artificial fruit flavor commonly used in the food industry for such flavors as orange
SIZIF [17.4K]

Answer:

A. 10.0 grams of ethyl butyrate would be synthesized.

B. 57.5% was the percent yield.

C. 7.80 grams of ethyl butyrate would be produced from 7.60 g of butanoic acid.

Explanation:

CH_3CH_2CH_2CO_2H(l)+CH_2CH_3OH(l)+H^+\rightarrow CH_3CH_2CH_2CO_2CH_2CH_3(l)+H_2O(l)

A

Moles of butanoic acid = \frac{7.60 g}{88 g/mol}=0.08636 mol

According to reaction ,1 mole of butanoic acid gives 1 mol of ethyl butyrate,then 0.08636 mol of butanoic acid will give :

\frac{1}{1}\times 0.08636 mol=0.08636 mol of ethyl butyrate

Mass of 0.08636 moles of ethyl butyrate =

0.08636 mol × 116 g/mol = 10.0 g

Theoretical yield = 10.0 g

Experimental yield = ?

Percentage yield of the reaction = 100%

Yield\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

100\%=\frac{\text{Experimental yield}}{10.0 g}\times 100

Experimental yield = 10.0 g

10.0 grams of ethyl butyrate would be synthesized.

B

Theoretical yield of ethyl butyrate  = 10.0 g

Experimental yield ethyl butyrate = 5.75 g

Percentage yield of the reaction = ?

Yield\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

=\frac{5.75 g}{10.0 g}\times 100=57.5\%

57.5% was the percent yield.

C

Moles of butanoic acid = \frac{7.60 g}{88 g/mol}=0.08636 mol

According to reaction ,1 mole of butanoic acid gives 1 mol of ethyl butyrate,then 0.08636 mol of butanoic acid will give :

\frac{1}{1}\times 0.08636 mol=0.08636 mol of ethyl butyrate

Mass of 0.08636 moles of ethyl butyrate =

0.08636 mol × 116 g/mol = 10.0 g

Theoretical yield = 10.0 g

Experimental yield = ?

Percentage yield of the reaction = 78.0%

Yield\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

78.0\%=\frac{\text{Experimental yield}}{10.0 g}\times 100

Experimental yield = 7.80 g

7.80 grams of ethyl butyrate would be produced from 7.60 g of butanoic acid.

8 0
3 years ago
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