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Ratling [72]
3 years ago
7

Is 3/8 greater than a.1/8 b.7/8 c.3/4 d.3/6

Mathematics
1 answer:
PtichkaEL [24]3 years ago
5 0
3/8 is greater than 1/8 because it is the same proportion and 3>1.
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This item is $9000 dollar and it is 90% off how much is the item? Step by step?
Daniel [21]

Answer:

The item costs $900 after the 90% off.

Step-by-step explanation:

After the 90% off discount, the item costs (100% - 90%) the cost of the original price.

Hence, \$9000 \cdot (100\% - 90\%)

= \$9000 \cdot 10\%

= \$900

Hope this helped!

5 0
3 years ago
Read 2 more answers
WILL MARK THE BRAINLEIST Find the surface of the rectangle prism ,show all of your work
trapecia [35]
The answer is 108 as your surface area.

Work:
To find surface area, you find the area of each side and add it all together. For the bottom and the top sides, it’s 6 x 3 which equals to 18. 18 + 18 = 36. Then, 3 x 4 = 12. 12 + 12 = 24. 6 x 4 = 24. 24 + 24 = 48. Then, you add it all together which equals to 108. If what I did doesn’t makes sense, I’ll explain it more detailed here.

So, I found the area of the bottom side and multiplied it by 2 to represent the top and bottom sides. Then, I did the same thing for the other sides if that makes sense. I’m really sorry if I’m not explaining it well. I’m better at doing the work in my head and not on paper or explaining it to other people.

Anyway, hope this helps!
3 0
3 years ago
Solve For X. Solve similar triangles (advanced)​
satela [25.4K]
4+3 = 7
7^2 +6^2
49+36 = 85
Radical85 = 9.21
So x will be 3.9
3 0
3 years ago
Multiply 3/sqrt17- sqrt2 by which fraction will produce an equivalent fraction with rational denominator
zzz [600]

Answer:

B.

Step-by-step explanation:

To simplify something that looks like \frac{\text{whatever}}{\sqrt{a}-\sqrt{b}} you would multiply the top and bottom by the conjugate of the bottom. So you multiply the top and bottom for this problem I just made by:

\sqrt{a}+\sqrt{b}.

If you had  \frac{\text{whatever}}{\sqrt{a}+\sqrt{b}}, then you would multiply top and bottom the conjugate of \sqrt{a}+\sqrt{b} which is \sqrt{a}-\sqrt{b}.

The conjugate of a+b is a-b.

These have a term for it because when you multiply them something special happens.  The middle terms cancel so you only have to really multiply the first terms and the last terms.

Let's see:

(a+b)(a-b)

I'm going to use foil:

First:  a(a)=a^2

Outer: a(-b)=-ab

Inner:  b(a)=ab

Last:    b(-b)=-b^2

--------------------------Adding.

a^2-b^2

See -ab+ab canceled so all you had to do was the "first" and "last" of foil.

This would get rid of square roots if a and b had them because they are being squared.

Anyways the conjugate of \sqrt{17}-\sqrt{2} is

\sqrt{17}+\sqrt{2}.

This is the thing we are multiplying and top and bottom.

3 0
3 years ago
Read 2 more answers
F(x) = 10x2 + 8, evaluate f(-3).
OlgaM077 [116]

Answer:

98

Step-by-step explanation:

f(x) = 10x² + 8

= 10(-3)² + 8

= 10 (9) + 8

= 90 + 8

= 98

5 0
3 years ago
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