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Fudgin [204]
2 years ago
8

Select the best answer.

Mathematics
1 answer:
expeople1 [14]2 years ago
7 0

Answer:

-sin x

Step-by-step explanation:

sin(3π/3+x)=sin (π+x)=-sin x

or

sin (π+x)=sin πcos x+cos π sin x=(0)cos x+(-1)sin x=0-sin x=-sin x

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a ladder leans against the sufe of a house. the angle of elevation of the ladder is 70 degrees when the bottom of the ladder is
nekit [7.7K]

Answer:

≈ 35.1 ft

Step-by-step explanation:

The model is a right triangle with ladder being the hypotenuse and the angle between the ground and the ladder is 70°

Using the cosine ratio, with l being the length of the ladder.

cos70° = \frac{adjacent}{hypotenuse} = \frac{12}{l} ( multiply both sides by l )

l × cos70° = 12 ( divide both sides by cos70° )

l = \frac{12}{cos70} ≈ 35.1 ( to the nearest tenth )

The ladder is approx 35.1 ft long

4 0
3 years ago
PLEASE HELP!!!! 20 POINTS
Kazeer [188]

Answer:

relative

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Graph 5x+y=2 and 5x-y=4
Andru [333]

Answer:

What do you mean

Step-by-step explanation:


7 0
4 years ago
Wayne spends 1/6th of an hour walking his dog. How much time does Wayne spend walking his dog in a week? *
Mila [183]

Answer:

10 minutes

Step-by-step explanation:

This is somewhat of a trick question and also incomplete.

Assuming he walks his dog 1/6th of an hour each week, he walks his dog 10 minutes per week.

If this is incorrect please tell me the complete question

3 0
3 years ago
Someone please be awesome and help me please :(
solong [7]

Answer:

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Step-by-step explanation:

x^2+\frac{b}{a}x+\frac{c}{a}=0

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared.  Whatever you add in, you must take out.

x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

Now we are read to write that one part (the first three terms together) as a square:

(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

I don't see this but what happens if we find a common denominator for those 2 terms after the square.  (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0

They put it in ( )

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

I'm going to go ahead and combine those fractions now:

(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}

x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}

Now subtract b/(2a) on both sides:

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Combine the fractions (they have the same denominator):

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

6 0
3 years ago
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