The first-serve percentage of a tennis player in a match is normally distributed with a standard deviation of 4.3%. If a sample

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The first-serve percentage of a tennis player in a match is normally distributed with a standard deviation of 4.3%. If a sample

of 15 random matches of the player is taken, the mean first-serve percentage is found to be 26.4%. What is the margin of error of the sample mean?

Mathematics

1 answer:

dem82 [27] · Answer 1 · 2021-12-08T13:15:53+03:00

The first-serve percentage of a tennis player in a match is normally distributed with a standard deviation of 4.3%. If a sample of 15 random matches of the player is taken, the mean first-serve percentage is found to be 26.4%. The margin of error of the sample mean is 83.71%.