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IceJOKER [234]
3 years ago
5

Help pls

Mathematics
2 answers:
babymother [125]3 years ago
4 0

Answer:

1). x = 10 m

2). x = 15 cm

3). x = 5 yd

4). AB = 10 units

Step-by-step explanation:

1). By Pythagoras theorem in the given triangle,

 a² + b² = c²

 Where 'c' = Hypotenuse

 a and b = Legs of the right triangle

 By substituting measures of the sides in the formula,

 x² = 8² + 6²

 x = \sqrt{100}

 x = 10 m

2). By using Pythagoras theorem in this triangle,

  x² = 9² + (12)²

  x² = 81 + 144

  x = \sqrt{225}

  x = 15 cm

3). By Pythagoras theorem,

  (13)² = x² + (12)²  

  169 = x² + 144

  169 - 144 = x²

  25 = x²

  x = 5 yd

4). If BD is a perpendicular bisector of AC,

  AD = CD = 6 cm

  By Pythagoras theorem in ΔABD,

  AB² = BD² + AD²

  AB² = 8² + 6²

  AB = \sqrt{100}

  AB = 10 units

siniylev [52]3 years ago
3 0
Here and don’t be shy like the anxiety

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Which expression uses the greatest common factor and the distributive property to rewrite the sum 42 + 72?
wlad13 [49]

Answer:

The answer is 6(7 + 12) ⇒ 1st answer

Step-by-step explanation:

* Lets explain how to solve the problem

- Factors are the numbers you multiply together to get another number

- Ex: 4 × 5 = 20 ⇒ 4 and 5 are the factors of 20

- Factors of a number n are the numbers that can multiplied together

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- Ex: The factors of 6 are 1 , 2 , 3 , 6 because 1 × 6 = 6 and 2 × 3 = 6

- The distributive property lets you multiply a sum by multiplying each

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* Lets solve the problem

- We want to find the greatest common factor in 42 + 72

∵ 42 = 1 × 42 , 2 × 21 , 3 × 14 , 6 × 7

∴ The factors of 42 are 1 , 2 , 3 , 6 , 7 , 14 , 21 , 42

∵ 71 = 1 × 72 , 2 × 36 , 3 × 24 , 4 × 18 , 6 × 12 , 8 × 9

∴ The factors of 72 are 1 , 2 , 3 , 4 , 6 , 8 , 9 , 12 , 18 , 24 , 36 , 72

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∵ The common factors between 42 and 72 are 1 , 2 , 3 , 6

∵ The greatest one of them is 6

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∵ 42 ÷ 6 = 7 and 72 ÷ 6 = 12

- We can write 42 + 72 as 6 × 7 + 6 × 12 and take 6 as a common factor

∵ 42 + 72 = 6 × 7 + 6 × 12

- Take 6 as a common factor

∴ 42 + 72 = 6(7 + 12)

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