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Eva8 [605]
3 years ago
12

What is the volume of this loaf of bread, assuming that the top part of the end of the loaf is a semi-circle? Show all work.

Mathematics
1 answer:
IRINA_888 [86]3 years ago
4 0

Answer:

Step-by-step explanation:

We would section the bread into a cuboid at the bottom and a semi cylinder at the top.

Considering the bottom, the formula for determining the volume of a cuboid is expressed as

Volume = length × width × height

Therefore,

Volume = 20 × 11 × 6 = 1320 cm³

Considering the semi cylinder,

The formula for determining the volume of a cylinder is expressed as

Volume = πr²h

Where

r represents the radius of the cylinder

h represents the height of the cylinder.

π = 3.14

Looking at the diagram,

Height = 20 cm

Diameter = 11 cm

Radius = diameter/2 = 11/2 = 5.5 cm

Since it is a semi cylinder, then

Volume = 1/2 × 3.14 × 5.5² × 20 = 949.85 cm³

Therefore, volume of this loaf of bread is

1320 + 949.85 = 2269.85 cm³

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e = 2.71828 is the Euler number

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The only information that we have is the mean number of an event(purchases) in a time interval. Each event is also independent fro each other. So you should suggest the Poisson distribution to model the number of purchases per​ minute.

b) What is the probability that in any one minute at least one purchase is​ made? ​

Either no purchases are made, or at least one is. The sum of the probabilities of these events is 1. So

P(X = 0) + P(X \geq 1) = 1

We want to find P(X \geq 1)

So

P(X \geq 1) = 1 - P(X = 0)

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\mu = 4*5 = 20

We have to find P(X = 7).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-20}*(20)^{7}}{(7)!} = 0.0005

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