Answer:
Percentage of the students scored higher than 89% = 65.87%
Step-by-step explanation:
We need to find the percentage of students who scored higher than 89% given mean = 84 and standard deviation = 5.
We can find the percentage of students who scored higher than 89% by using z-score.
The formula for z-score is:
μ= mean = 84
σ=standard deviation = 5
x= random number = 89
Putting these values, we get
Now, we know that we need to find students who score greater than 89%
so P(X>89) or P(X>1),
finding value of z= 1 which can be easily found using z score tables.
By looking at table we get the value of z = 0.3413
Subtracting the value of z from 1 we get
Percentage of the students scored higher than 89% = 1-0.3413 = 0.6587 or 65.87%
Answer:
(0, 3), (4, 9), (6, 9), (7, 17)
Step-by-step explanation:
Answer:
$5659.11
Step-by-step explanation:
We are given;
- Time of loan maturity is 5 years
- Rate of compound interest is 7% compounded quarterly
- Principal amount of the car is $4000
We are required to determine the total amount he paid at the end of 5 years..
The concept being tested is compound interest;
We are going to use the compound interest formula;
Amount = P(1+r/100)^n
Where P is the the principal amount
r is the rate of interest
n is the interest periods
In this case;
n = (5 × 4) = 20
r = 7 ÷ 4 = 1.75 ( as the money was compounded quarterly)
Thus;
Amount =$ 4000 ( 1 + 1.75)^20
= $4000 (1.0175)^20
= $5659.11
Therefore, the money that Joe will have paid at the end of 5 years is $5659.11
Answer:
$6.73
Step-by-step explanation:
1 bacon = $0.55
5 x $0.55 = $2.75
1 egg = $1.24
2 x $1.24 = $2.48
1 apple juice = $1.50
$2.75
$2.48
+ $1.50
————
$6.73
Therefore, your answer is $6.73.