Gimme Brainliest.
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Answer: DoDM 5200.01, DoD Information Security Program
Explanation:
The document that provides basic guidance and regulatory requirements for derivative classification
for DoD personnel is referred to as the DoDM 5200.01, DoD Information Security Program.
The purpose of this is to help in the promotion of an effective way that can be used in the classification, protection, and application of applicable instructions.
Answer and Explanation:
Using Javascript:
Class Dog{
var healthScores=[];
Constructor(name, age, ...healthScores) {this.name=name;
this.age=age;
this.healthsScores=healthScores;
}
checkObject(new Dog){
If(new Dog.name===this.name,new Dog.age===this.age, new Dog.healthScores===this.healthScores){return true;
}
else{
console.log("objects are not equal");
}
}
}
To call the method checkObject:
var Tesa = new Dog(Tes,1,[45,46,82]);
var Bingo = new Dog(bing,2,[43,46,82]);
Bingo.checkObject(Tesa);
Note: we have used ES6(latest version of Javascript) where we passed the healthScore parameter(which is an array) to our constructor using the spread operator.
Answer:
dual-core (two), quad-core (four) and octa-core (eight)
Explanation:
These are the most common according to my research.
If I helped you, can I please have brainliest?
Have a great day/night!
Answer:
The answer is below
Explanation:
Given that:
Frame transmission time (X) = 40 ms
Requests = 50 requests/sec, Therefore the arrival rate for frame (G) = 50 request * 40 ms = 2 request
a) Probability that there is success on the first attempt = 
but k = 0, therefore Probability that there is success on the first attempt = 
b) probability of exactly k collisions and then a success = P(collisions in k attempts) × P(success in k+1 attempt)
P(collisions in k attempts) = [1-Probability that there is success on the first attempt]^k = ![[1-e^{-G}]^k=[1-0.135]^k=0.865^k](https://tex.z-dn.net/?f=%5B1-e%5E%7B-G%7D%5D%5Ek%3D%5B1-0.135%5D%5Ek%3D0.865%5Ek)
P(success in k+1 attempt) =
Probability of exactly k collisions and then a success = 
c) Expected number of transmission attempts needed = probability of success in k transmission = 
