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3 years ago

Find the equation of a circle with center at the origin and x intercepts 10 and -10

1 answer:

7 0

The standard equation for a circle with center at the origin is
${x}^{2} + {y }^{2} = {r}^{2}$
and as the radius of thr circle is 10 that is the value if r so
${x}^{2} + {y}^{2} = {10}^{2}$
or
${x}^{2} + {y}^{2} = 100$
is the equation of the circle

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Answer:

We would use to describe numbers from 1 - 6.

Step-by-step explanation:

We represent the flavors as a set in Roster form.

F = {grape, strawberry, lemon, orange, apple, watermelon}

Note that that there are 6 flavors.

i.e., n(F) = 6

Since we have to assign a number for each flavor, and there are 6 flavors, we would use to describe numbers from 1 - 6.

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3 years ago

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konstantin123 [22]

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Step-by-step explanation:

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on july 20th 2018, 1 U.S. dollar (1$) war worth 0.87 euros (0.87) how much $150 was worth in euros on that day

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X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y

andriy [413]

The result for the given normal random variables are as follows;

a. E(3X + 2Y) = 18

b. V(3X + 2Y) = 77

c. P(3X + 2Y < 18) = 0.5

d. P(3X + 2Y < 28) = 0.8729

<h3>What is normal random variables?</h3>

Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.

Now, according to the question;

The given normal random variables are;

E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.

Part a.

Consider E(3X + 2Y)

$\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}$