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Paraphin [41]
4 years ago
5

Which value is closest to (7 x 108) + (5 x 105)?

Mathematics
2 answers:
LekaFEV [45]4 years ago
8 0

Answer:

C)12 x 108 has the closest value.

Step-by-step explanation:

Firstly, (7 x 108) + (5 x 105) is equal to 756 + 525 which is equal to 1281.

A)7 x 108= 756

B)12 x 1013= 12156

C)12 x 108=1296

D)7 x 1013=7091

Fiesta28 [93]4 years ago
8 0
C has the closest value!!!!!!!
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Find the next two terms 1/8, 2/7,1/2,4/5
Verizon [17]

Answer:  5/4 and 6/3

Step-by-step explanation:

1/2 can be written as 3/6 so the series now becomes,

1/8 , 2/7 , 3/6 , 4/5 ,…….

i think you can now guess the answer, look at the<u> numerators which are increasing by ‘1’ </u>and then look at the <u>denominators which are decreasing by ‘1’.</u>

so the next number in the series is, 1/8 , 2/7 , 3/6 , 4/5 , 5/4 , 6/3

hope this helped

5 0
3 years ago
Is this a right angle?<br>use the Pythagorean theorem to find out!​
Komok [63]

Answer:

Yes this is a right angle triangle

Step-by-step explanation:

h*h=p*p+b*b

5*5=4*4+3*3

25=16+9

25=25

6 0
4 years ago
A line passes through the points (3,9) and (5,1). What is the equation in point slope?
Kipish [7]
The slope is equal to -4.
Hope this helps!
8 0
4 years ago
Please Help ASAP I dont understand this <br><br>​
antiseptic1488 [7]

To find m<3, we can use the angle sum of triangles, in which the addition all angles in a triangle must be equal to 180°.

In this case:

m<3 +52°+29° = 180°

m<3 + 81° = 180°

m<3 = 180°-81°

m<3 = 99°

To find m<4, we can use adjacent angles on a straight line, where the addition of angles on a straight line must be 180°.

In this case:

m<4 + 99° = 180°

m<4 = 180°-99°

m<4 = 81°

Therefore m<3 is 99° while m<4 is 81°.

Hope it helps!

4 0
3 years ago
Sick-leave time used by employees of a firm in a course of one month has approximately normal distribution, with a mean of 200 h
Usimov [2.4K]

Answer:

a)0.62% probability that total sick leave for next month will be less than 150 hours.

b) 225.6 hours should be budgeted for sick leave if that amount is to be exceeded with a probability of only 0.10.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 200, \sigma = \sqrt{400} = 20

a.Find the probability that total sick leave for next month will be less than 150 hours.

This probability is the pvalue of Z when X = 150. So:

Z = \frac{X - \mu}{\sigma}

Z = \frac{150 - 200}{20}

Z = -2.5

Z = -2.5 has a pvalue of 0.0062.

So there is a 0.62% probability that total sick leave for next month will be less than 150 hours.

b.In planning schedules for next month, how much time should be budgeted for sick leave if that amount is to be exceeded with a probability of only 0.10.

This is the value of X when Z has a pvalue of 0.90. So Z = 1.28

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 200}{20}

X - 200 = 20*1.28

X = 225.6

225.6 hours should be budgeted for sick leave if that amount is to be exceeded with a probability of only 0.10.

6 0
4 years ago
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