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Alja [10]
4 years ago
14

A variable force of 6x−2 pounds moves an object along a straight line when it is x feet from the origin. Calculate the work done

in moving the object from x = 1 ft to x = 15 ft. (Round your answer to two decimal places.)
Mathematics
1 answer:
Tamiku [17]4 years ago
8 0

Answer:

644 J

Step-by-step explanation:

F = 6x -2

x1 = 1 ft , x2 = 15 ft

Let dW be the small amount of work done in moving with a small distance dx.

dW = F dx

Now integrate both sides within proper limits

\int dW = \int_{1}^{15}(6x -2)dx

W =[3x^{2}-2x]_{1}^{15}

W = (3 x 225 - 2 x 15) - (3 - 2)

W = 644 J

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After taking a 70 point test, a student guesses that he got 65 points correct. Later he finds out he got 67 points
Nataliya [291]

Answer:

Percent error = 4.29%

Step-by-step explanation:

Percent error can be defined as a measure of the extent to which an experimental value differs from the theoretical value.

Mathematically, it is given by this expression;

Percent \; error = \frac {experimental \;value - theoretical \; value}{ theoretical \;value} *100

Given the following data;

Experimental value = 67

Theoretical value = 70

Substituting into the equation, we have;

Percent \; error = \frac {67 - 70 }{ 70} *100

Percent \; error = \frac {3}{70} *100

Percent \; error =  0.04286 *100

Percent error = 4.29%

4 0
3 years ago
I'LL NAME YOU BRAINIEST!!!! Find the equation for the line which contains the points (0, -3) and (14, 0). Express your answer in
vova2212 [387]
It’s 5+3x 10-1= 21345
5 0
4 years ago
What does x equal? help pls c:
sweet-ann [11.9K]

Answer:

this question answer is 11

8 0
3 years ago
Could someone please help on this question? I’m giving 20 points and brainliest but I need it quickly so please help!
AnnZ [28]
<h3>Answer:  HF = 5</h3>

=============================================

Explanation:

Refer to the diagram below. I'm adding in points A and B, which are marked in blue. I'm also adding in variables x, y, and z.

The goal is to find HF, so let's make that equal to x. This is also equal to HB because they are radii of the same circle.

Let y be the length of segments JA and JB.

Let z be the length of segments CF and CA.

So in short we have

  • x = HF = HB
  • y = JA = JB
  • z = CF = CA

We know that

  • CH = 13
  • HJ = 19
  • CJ = 22

This must mean

  • CH = CF+HF = z+x = 13
  • HJ = HB+JB = x+y = 19
  • CJ = CA+JA = z+y = 22

Or in short,

  • z+x = 13
  • x+y = 19
  • z+y = 22

Let's solve the first equation for z to get z = -x+13. I subtracted x from both sides.

Now plug this into the third equation to get

z+y = 22

(z) + y = 22

(-x+13) + y = 22 ... replace z with -x+13

-x+13+y = 22

-x+y+13 = 22

-x+y = 22-13 .... subtract 13 from both sides

-x+y = 9

------------------------------------

So we have this reduced system of equations of two variables and two equations

  • x+y = 19 ... found earlier
  • -x+y = 9 .... what we just found above

Add the equations straight down. This is the elimination property.

Doing so leads to the x terms canceling out since x + (-x) = 0x = 0

The y terms add to y+y = 2y

The terms on the right hand side add to 19+9 = 28

We are left with 2y = 28 which solves to y = 28/2 = 14.

If y = 14, then,

x+y = 19

x+14 = 19

x = 19-14

x  = 5

In which we can then say

z = -x+13

z = -5+13

z = 8

Though we don't need to find z (unless you're curious about it).

Since x = 5, and we set HF equal to x, this means that HF = 5.

6 0
3 years ago
3. Let sin 21 = 0.358. What is the value of x for cos x=0.358?
r-ruslan [8.4K]

Answer:

\cos(69)

Step-by-step explanation:

We will use the co-function identity for sine, where:

\sin(x)=\cos(90-x)

Since sin(21)=0.358=cos(x). This means that:

21=90-x

Solve for x. Add x to both sides:

x+21=90

Subtract 21 from both sides:

x=69\textdegree

Hence:

\sin(21)=\cos(69)\approx0.358

6 0
3 years ago
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