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3 years ago

PLEASE HELP

Mathematics

2 answers:

bearhunter [10]3 years ago

7 0

Answer:

i'm pretty sure 1.96×10-3 m³

is the right answer

Nana76 [90]3 years ago

7 0

V = pi r^2 h
Substitute in the values
= 3.14 x 5^2 x 0.25
= 19.625
Hope this helps, have a nice day! :)

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The m6 = (11x + 8)° and m7 = (12x – 4)° What is the measure of 4? m4 = 40° m4 = 48° m4 = 132° m4 = 140°

bezimeni [28]

M< 6 = m< 7 (vertical angles)
11x + 8 = <span>12x – 4
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m<4 = 180 - m<6
m<4 = 180 - 140
m<4 = 40

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Step-by-step explanation:

We have to calculate a 99% confidence interval for the difference between the true average load for the fiberglass beams and that for the carbon beams.

The sample 1 (Fiberglass), of size n1=26 has a mean of 33.4 and a standard deviation of 2.2.

The sample 2 (Carbon), of size n2=26 has a mean of 42.8 and a standard deviation of 4.3.

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The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{2.2^2}{26}+\dfrac{4.3^2}{26}}\\\\\\s_{M_d}=\sqrt{0.186+0.711}=\sqrt{0.897}=0.9473$

The critical t-value for a 99% confidence interval is t=2.678.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_{M_d}=2.678 \cdot 0.9473=2.537$

Then, the lower and upper bounds of the confidence interval are:

$LL=M_d-t \cdot s_{M_d} = -9.4-2.537=-11.937\\\\UL=M_d+t \cdot s_{M_d} = -9.4+2.537=-6.863$

The 99% confidence interval for the difference between the true average load for the fiberglass beams and that for the carbon beams is (-11.937, -6.863).

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