Question

the circle is centered at the point (3,2), and the length of its radius is 5. what is the equation of the circle?

Answer 1

Answer:

(x-3)^2+(y-2)^2=25

Step-by-step explanation:

So the equation of a circle in center-radius form is (x-h)^2+(y-k)^2=r^2

where (h,k) is the center and r is the radius.

You are given the center is (3,2) so (h,k)=(3,2) so replace h with 3 and k with 2.

We are also given the radius is 5 so r is 5.

So the equation for the circle is (x-3)^2+(y-2)^2=5^2

or (x-3)^2+(y-2)^2=25.

Answer 2

Answer: Equation of the circle is,

$(x-3)^2+(y-2)^2=25$

Step-by-step explanation:

Since, center-radius form of circle is,

$(x-h)^2+(y-k)^2=r^2$

Where, (h, k) is the center of the circle,

r is the radius of the circle,

Here,

r = 5 units, h = 3, k = 2,

Hence, the equation of the circle,

$(x-3)^2+(y-2)^2=25$