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QveST [7]
3 years ago
7

Solve y=x^2 + 7 for x

Mathematics
1 answer:
crimeas [40]3 years ago
5 0
Hello! To solve for x means to isolate x:

y = x^2 + 7
y - 7 = x^2
sqrt(y - 7) = x

Answer:
x = sqrt(y - 7)

Hope this helps!
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X-(-27)=35-12 solving equation
irakobra [83]
-4 is the correct answer
35-12 =25
-4 - ( -27) = -4 + 27 =23
4 0
3 years ago
What is the slope of the line that contains the points (4, 3) and (2, 7)?​
zubka84 [21]

Answer:

-2

Step-by-step explanation:

given 2 points on a line (x1, yx) and (x2,y2)

the formula for slope, m  = (y2-y1) / (x2-x1)

in this case,

x1 = 4, y1 = 3, x2 = 2, y2 = 7

Hence,

m  = (7-3) / (2-4) = 4 / -2 = -2

8 0
3 years ago
Ian measured a city park and made a scale drawing. In real life, the soccer field is 114 meters long. It is 19 millimeters long
ioda

Answer:

1 mm : 6 m

Step-by-step explanation:

Take the 19 mm and divide it by 114 meters. to get the scale

19/114  =  1/6

1 mm : 6 meters

8 0
3 years ago
Find the product of 2(5.9) mentally using the distributive property.
VARVARA [1.3K]

2(5.9) is 11.8

Hopefully i is right I did this in my head.


7 0
3 years ago
A group of three undergraduate and five graduate students are available to fill certain student government posts. If four studen
creativ13 [48]

Answer:

Pr = 0.4286

Step-by-step explanation:

Given

Let

U \to\\ Undergraduates

G \to Graduates

So, we have:

U = 3; G =5 -- Total students

r = 4 --- students to select

Required

P(U =2)

From the question, we understand that 2 undergraduates are to be selected; This means that 2 graduates are to be selected.

First, we calculate the total possible selection (using combination)

^nC_r = \frac{n!}{(n-r)!r!}

So, we have:

Total = ^{U + G}C_r

Total = ^{3 + 5}C_4

Total = ^8C_4

Total = \frac{8!}{(8-4)!4!}

Total = \frac{8!}{4!4!}

Using a calculator, we have:

Total = 70

The number of ways of selecting 2 from 3 undergraduates is:

U = ^3C_2

U = \frac{3!}{(3-2)!2!}

U = \frac{3!}{1!2!}

U = 3

The number of ways of selecting 2 from 5 graduates is:

G = ^5C_2

G = \frac{5!}{(5-2)!2!}

G = \frac{5!}{3!2!}

G =10

So, the probability is:

Pr = \frac{G * U}{Total}

Pr = \frac{10*3}{70}

Pr = \frac{30}{70}

Pr = 0.4286

5 0
3 years ago
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