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Scrat [10]
3 years ago
8

A teacher has four books—A, B, C, and D—to assign to four students in any order he prefers. Set S includes all possible arrangem

ents of the four books. Set X includes all possible arrangements when book C is chosen first and D is chosen second. Which notation is correct? If book C is chosen first and D is chosen second, in how many ways can the teacher assign the books?
Mathematics
2 answers:
uranmaximum [27]3 years ago
3 0
The Answers Are :
X, S and 2
Katen [24]3 years ago
3 0

Answer with explanation:

The Number of Books Possessed by the teacher = A, B,C,D

Total possible arrangement of the books,in which order is Important,we will use the concept of Permutation

S={_{4}^{4}\textrm{P}=\frac{4!}{(4-4)!}=\frac{4!}{0!}=4\times 3\times 2\times 1=24

So, there are 24 elements in set S.

Number of Elements in the set X

              =taking CD as a first element and Either A as third and B as fourth or B as third and A as fourth.

=1+1

=2 ways

Or

Keeping CD as one book, then there are 2 books left,which can be arranged as

=1×2×1

=2 ways

So, if book C is chosen first and D is chosen second, number of ways the teacher can assign the books

     = 2 ways

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Guys Pls Help ASAP! Will Give Brainliesttt. <br><br> Thxx
Allisa [31]

Answer:

23. x= -2/5 x= -5

24. x= 3/4 x= -1/6

25. x= 7/3. x= -5/4

26. x= 3 x= -2/3

27. x= 1. x= -2/7

28. x= 9/4. x= -1/3

29. x= 2/5 x= 1/3

30. x= 2/3 x= 1/2

6 0
3 years ago
A hummingbird eggs’ mass is approximately 0.374 milligram. What is the mass of 4 Hummingbird eggs?
antoniya [11.8K]

it would be 1.496 milligrams. i hope this helps and i used a calculator

5 0
3 years ago
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What is the greatest common factor of 44c^5, 22c^3 and 11c^4
Alexxandr [17]

\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

<em><u>Solution:</u></em>

Given that, we have to find the greatest common factor of 44c^5, 22c^3 , 11c^4

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}

First find the GCF of numbers and then find the GCF of variables and then multiply them together

<em><u>Step 1: GCF of 44, 22 and 11</u></em>

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

\text{ Step 2: GCF of }c^5, c^3 , c^4

c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1

Thus the greatest common factor is c^3

Step 3: Multiply the GCF of 44, 22, 11 and GCF of c^5, c^3 , c^4

\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3

Thus \text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

8 0
3 years ago
Pls help me with this
alexgriva [62]

Answer:

x = 1.5

Step-by-step explanation:

Given

\frac{x}{2} \geq 0.75

\frac{x}{2} < 2.5

Required

Find the value of x.

First, the inequalities need to be rewritten and merged;

if \frac{x}{2} \geq 0.75, then

0.75 \leq \frac{x}{2}

Multiply both sides by 2

2 * 0.75 \leq \frac{x}{2} * 2

1.5 \leq x

Similarly;

\frac{x}{2} < 2.5

Multiply both sides by 2

2 * \frac{x}{2} < 2.5 * 2

x < 5

Merging these results together; to give

1.5 \leq x < 5

This means that the range of values of x is from 1.5 to 4.9999....

From the question, x is the smallest rational number; from the range above (1.5 \leq x < 5), the minimum value of x is 1.5 and 1.5 is a rational number;

Hence, x  = 1.5

4 0
3 years ago
Plz help will give brainliest!!
cluponka [151]

Answer:

66 R30

Step-by-step explanation:

:) :) :/ probably wrong

8 0
3 years ago
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