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3 years ago

Solve for x: x − 2 > 2x + 12. (5 points)

Mathematics

2 answers:

BigorU [14]3 years ago

4 0

X & gt; -14 is your answer to your question

emmainna [20.7K]3 years ago

4 0

Answer:

The answer is x < -14

Step-by-step explanation:

To solve this question, you have to get the x on one side of the inequality using the addition and subtraction property of equality. So, add 2 on both sides. This gives you x > 2x + 14. Then, subtract 2x from both sides, which gives you -x > 14. Finally, divide both sides by -1 and flip the inequality sign, as dividing or multiplying by a negative number in an inequality flips the symbol. This gives you x < -14, or option 4.

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How many real and complex roots exists for a polynomial?

solmaris [256]

Step-by-step explanation:

whenever a complex number is a root of a polynomial with real coefficients, its complex conjugate is also a root of that polynomial. as an example, we'll find the roots of the polynomial..

x^5 - x^4 + x^3 - x^2 - 12x + 12.

the fifth-degree polynomial does indeed have five roots; three real, and two complex.

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3 years ago

8 percent of what number is 2

Sedbober [7]

8%×n=2. 2÷8/100=2×100/8=100/4=25. so the answer is 25.

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3 years ago

I need help... how do you solve this? I'm so sorry i just dont understand it

Novosadov [1.4K]

I need a question or a problem to solve??

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3 years ago

Explain why any of the four operations placed between two terms 5 and -3 sqrt (8) will result in an irrational number

Gnoma [55]

Sum/difference:

Let

$x = 5 + (-3\sqrt{8}) = 5-3\sqrt{8}$

This means that

$3\sqrt{8} = 5-x \iff \sqrt{8} = \dfrac{5-x}{3}$

Now, assume that $x$ is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that $x$ was rational, which proves that the sum/difference of the two given terms was irrational

Multiplication/division:

The logic is actually the same: if we multiply the two terms we get

$x = -15\sqrt{8}$

if again we assume x to be rational, we have

$\sqrt{8} = -\dfrac{x}{15}$

But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.

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3 years ago

Can someone please help!! <br> I need the answer and explanation pls

Ira Lisetskai [31]

Step-by-step explanation:

percentage of green marbles=

(total green marbles÷ total marbles )×100

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2 years ago