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Zina [86]
3 years ago
10

E bisects line segment df. df=2y, and ef=8y-3. find de, ef, and df.

Mathematics
1 answer:
Usimov [2.4K]3 years ago
8 0

1/2DF = EF

1/2(2y) = 8y - 3

  • Multiply 1/2 * 2y.

y = 8y - 3

  • Subtract 8y from both sides.

-7y = -3

  • Divide both sides by -7.

y = 3/7

  • Plug 3/7 for y into DF and EF.

DF: 2(3/7) = 6/7

EF: 8(3/7) - 3 = 24/7 - 3 = 3/7

EF = DE because they are bisected, so DE = 3/7

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slope =  \frac{7 - ( - 5)}{6 - ( - 2)}  \\

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Answer:

y = 3x - 9

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To write a line with a slope of 3, set the coefficient of x to be 3:

y = 3x

But notice, if we evaluate x when it is equal to 2, we get 2*3=6, but we want it to be -3. Therefore, we just subtract 9 from the equation:

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Find the value of x and y. Show all your work neat and<br> in order.
Mazyrski [523]

Answer:

x = 21°

y = 29°

Step-by-step explanation:

a) Solving for x

Note that:

(3x - 3)° and 60° are Alternate interior angles, and alternate interior angles are equal to each other, hence:

3x - 3 = 60° (Alternate interior angles)

Add 3 to both sides

3x - 3 +3 = 60 + 3

3x = 63°

x = 63°/3

x = 21°

b) Solving for y

Notes that:

(3x - 3)° and (4y + 4)° are Consecutive interior angles and the sum consecutive interior angles is 180°

3x - 3 + 4y + 4 = 180°

3x + 4y - 3 + 4 = 180°

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Note that x = 21

Hence

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Solve for x. what is aswer
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