3 years ago

E bisects line segment df. df=2y, and ef=8y-3. find de, ef, and df.

Mathematics

1 answer:

Usimov [2.4K]3 years ago

8 0

1/2DF = EF

1/2(2y) = 8y - 3

Multiply 1/2 * 2y.

y = 8y - 3

Subtract 8y from both sides.

-7y = -3

Divide both sides by -7.

y = 3/7

Plug 3/7 for y into DF and EF.

DF: 2(3/7) = 6/7

EF: 8(3/7) - 3 = 24/7 - 3 = 3/7

EF = DE because they are bisected, so DE = 3/7

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