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3 years ago

For the Relation (3,0), (4,-1), (5,-2), (6,-3) what is the range?

Mathematics

1 answer:

marissa [1.9K]3 years ago

8 0

Step-by-step explanation: The range of a relation is the set of all the y-terms of the relation. So here, the range will be the set of all the y-terms.

The y-terms will be the second number inside the ordered pairs. The range is also listed from least to greatest.

Answer is attached in the image provided.

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Need help filling in the blanks.. also not sure if the answers i filled in are correct or not.

tino4ka555 [31]

Answer:

See below.

Step-by-step explanation:

For item 2:

The Net Price Rate = 276 / 460 = 0.60 = 60 % (answer).

Item 3: Net Price Rate = 3247 * 100 / 3820 = 85% (answer).

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Item 5 Item's Net Price = 987 * 0.675 = $666.23 (answer).

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Item 8: First find the list place $x:

0.90* 0.80 * 0.70x = 252 ( the 0.90 , 0.80 and 0.70 come from 100 - 10% = 1 - 0.10 = 0.90 and so on)

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3 years ago

A telemarketer is paid a fixed amount of $15 in addition to $2 per call. If the average cost per call is $3, find the number of

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2 years ago

How much feet is in a mile

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Step-by-step explanation:

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3 years ago

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What is the probability that a random person who tests positive for a certain blood disease actually has the disease, if we know

xeze [42]

Answer:

Step-by-step explanation:

Hello!

Any medical test used to detect certain sicknesses have several probabilities associated with their results.

Positive (test is +) ⇒ P(+)

True positive (test is + and the patient is sick) ⇒ P(+ ∩ S)

False-positive (test is + but the patient is healthy) ⇒P(+ ∩ H)

Negative (test is -) ⇒ P(-)

True negative (test is - and the patient is healthy) ⇒ P(- ∩ H)

False-negative (test is - but the patient is sick) ⇒ P(- ∩ S)

The sensibility of the test is defined as the capacity of the test to detect the sickness in sick patients (true positive rate).

⇒ P(+/S) = P(+ ∩ S)

P(S)

The specificity of the test is the capacity of the test to have a negative result when the patients are truly healthy (true negative rate)

⇒ P(-/H) = P(- ∩ H)

P(H)

For this particular blood disease the following probabilities are known:

1% of the population has the disease: P(S)= 0.01

95% of those who are sick, test positive for it: P(+/S)= 0.95 (sensibility of the test)

2% of those who don't have the disease, test positive for it: P(+/H)= 0.02

The probability of a person having the blood sickness given that the test was positive is:

P(S/+)= P(+ ∩ S)

P(+)

The first step you need to calculate the intersection between both events + and S, for that you will use the information about the sickness prevalence in the population and the sensibility of the test:

P(+/S) = P(+ ∩ S)

P(S)

P(+/S)* P(S) = P(+ ∩ S)

P(+ ∩ S) = 0.95*0.01= 0.0095

The second step is to calculate the probability of the test being positive:

P(+)= P(+ ∩ S) + P(+ ∩ H)

Now we know that 1% of the population has the blood sickness, wich means that 99% of the population doesn't have it, symbolically: P(H)= 0.99

Then you can clear the value of P(+ ∩ H):

P(+/H) = P(+ ∩ H)

P(H)

P(+/H)*P(H) = P(+ ∩ H)

P(+ ∩ H) = 0.02*0.99= 0.0198

Next you can calculate P(+):

P(+)= P(+ ∩ S) + P(+ ∩ H)= 0.0095 + 0.0198= 0.0293

Now you can calculate the asked probability:

P(S/+)= P(+ ∩ S) = 0.0095 = 0.32

P(+) 0.0293

I hope it helps!

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