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amm1812
3 years ago
7

Order the side lengths HI, IK, HJ, IJ, and KJ from least to greatest.​

Mathematics
1 answer:
puteri [66]3 years ago
3 0

Answer:

KJ, IK, HI, HJ, IJ

Explanation:

The shortest side of a triangle is always opposite the smallest angle, and the longest side is always opposite the largest angle

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How do you solve 2x=12+2y
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2(x) - [12 + 2y) ➡ 0
2(x - y - 6)
2 ➡0 {It doesn't have any solution for the equation}
x - y - 6 ➡0
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The slope = 1

Therefore your answer would have to be ➡
y= 6 over -1 ; x = 6 over 1 ; slope = 1

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4 years ago
Joan is 5 years older than Ellen, and 3 years ago their sum of their ages is 17, in how many years will Joan be 21?
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2 years ago
The answer to #2?? I already have the graph but I still need the answer
Sidana [21]
If we have 

y = 6x + 1 and x - y = 11, we can take advantage of  y - y = 0 as follows:
                                         Subtract x from both sides of the 2nd equation:
                                         -y = 11 - x

Now combine 

 y = 6x + 1
-y = 11 - x
--------------
0 = 5x + 12.  Solving for x, x = -12/5.     Using the equation above, find y:
                                                               -y = 11 - x
                                                                   = 11 - (-12/5)
                                                                   = 55/5 + 12/5 = 67/5

Then the solution is (-12.5, 67/5).

                      
3 0
4 years ago
Find the point, M, that divides segment AB into a ratio of 2:3 if A is at (0.15) and B is at (20.0)
timama [110]

Answer:

M = (8,9)

Step-by-step explanation:

Notice that the points (0,15), and (20,0) form with the origin of coordinates (0,0),  a right angle triangle (please see attached image). This triangle has twon perpendicular sides of length 15 and 20 respectively. Therefore, we can find the length of the segment that joins points A (0,15) and B (20,0) by finding the length of the hypotenuse in a right angle triangle (with the Pythagorean Theorem):

AB=\sqrt{15^2+20^2} =\sqrt{625} =25

Now, to get a 2:3 proportion on Segment AB which is of length 25, we need to divide it in five equal parts (see the picture on the right of the attached image), and place point M at two of these divisions from point A (0,15) and along segment AB.

In order to find the appropriate location in (x,y) coordinates, we consider a smaller triangle (pictured in orange in the image) that is similar to the first larger triangle (pictured in blue). Notice that if the length of AB is 25,  each of its five equal divisions would be of length "5", and therefore two of them will render a length of "10" (which is the hypotenuse of this smaller right angle triangle.

Now, in order to find the sides of this smaller triangle (which can give us the clues on the horizontal and vertical coordinates of point M), we can use proportions.

To find the length "x" of the horizontal side , we do:

\frac{x}{10} =\frac{20}{25} \\x=\frac{10*20}{25} \\x=8

To find the length "y" of the vertical side , we do:

\frac{y}{10} =\frac{15}{25} \\y=\frac{10*15}{25} \\y=6

Then, the coordinate "x" of point M will be "8", while we can calculate the y position of point M subtracting "6" from 15 (the length of the vertical side in the original triangle). This gives us the coordinates (8,9) for point M as marked in orange in the picture.

7 0
3 years ago
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