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3 years ago

Can someone please help me please?

Mathematics

1 answer:

jeka57 [31]3 years ago

8 0

B because if you take it it would be b

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At the start of the month, Jodie had sold 885 copies of her new book. At the end of the month, she had sold 1,364 copies of her

ozzi

Approximately $ 31419 profit is earned from selling books in entire month

Solution:

Given that Jodie had sold 885 copies of her new book

At the end of the month, she had sold 1,364 copies of her book

We have to determine the profit earned in the entire month

From given information,

Start of month sale = 885 copies

End of month sale = 1364 copies

Total copies of books sold = Start of month sold + end of month sold

Total copies of books sold = 885 + 1364 = 2249

Also given that each book profit is $ 13.97

Profit of 1 book = $ 13.97

Therefore for 2249 books, profit earned is given as:

Profit of 2249 books = $ 13.97 x 2249 = 31418.53

Therefore approximately $ 31419 profit is earned from selling books in entire month

5 0

3 years ago

Factorize this expression completely using (a-b)² formula 3a²- 36a + 108

Novosadov [1.4K]

Answer:

$3a^2 - 36a + 108 = (\sqrt{3}a - 6\sqrt{3} )^2$

Step-by-step explanation:

$3a^2 = (\sqrt{3} a)^2\\108 = 9 \times 4 \times 3= 3^2 \times 2^2 \times 3 = (3\times2 \sqrt{3} )^2 = (6\sqrt{3})^2$

$so, a = \sqrt{3} a \ , \ b = 6\sqrt{3} \\\\(a - b)^2 = a^2 -2ab + b^2\\\\-36a = -2ab\\\\-36a = -2 \times \sqrt{3} a \times 6\sqrt{3}$

Therefore ,

$3a^2 - 36a + 108 = (\sqrt{3}a )^2 - 2(\sqrt{3}a \times 6\sqrt{3} ) + (6\sqrt{3} )^2 = (\sqrt{3}a - 6\sqrt{3} )^2$

6 0

3 years ago

Find the circumferences of both circles

nika2105 [10]

Answer:

Both circles

Step-by-step explanation:

7 0

3 years ago

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Emelina write the equation of a line in point slope form as shown below

Lynna [10]

Answer: Well, I don't see the points what are the points and I will write you the equation

4 0

3 years ago

HELP!!!!!!!!!!!!!!!!

lesya [120]

$2x^{2}$ is a monomial (since it is all connected by multiplication) and since it is in the degree of 2, that makes it a quadratic.

-2 is a constant (since it doesn't have variables) and it is a monomial (since it is all connected by multiplication)

3x-9 is a binomial (since it has two terms, not connected by multiplication) and since it has x in the power of 1, that makes it a linear equation.

Finally, $-3x^{2}$ -6x + 9 is a trinomial (since it has 3 terms connected by either addition or subtraction) and since the degree of the polynomial is 2, that makes it a quadratic.

8 0

3 years ago

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