Answer:
the only solution is 0
Step-by-step explanation:
Answer:
The approximate probability that more than 360 of these people will be against increasing taxes is P(Z> <u>0.6-0.45)</u>
√0.45*0.55/600
The right answer is B.
Step-by-step explanation:
According to the given data we have the following:
sample size, h=600
probability against increase tax p=0.45
The probability that in a sample of 600 people, more that 360 people will be against increasing taxes.
We find that P(P>360/600)=P(P>0.6)
The sample proposition of p is approximately normally distributed mith mean p=0.45
standard deviation σ=√P(1-P)/n=√0.45(1-0.45)/600
If x≅N(u,σ∧∧-2), then z=(x-u)/σ≅N(0,1)
Now, P(P>0.6)=P(<u>P-P</u> > <u>0.6-0.45)</u>
σ √0.45*0.55/600
=P(Z> <u>0.6-0.45)</u>
√0.45*0.55/600
Answer:
12.3
Step-by-step explanation:
Step 1
We find the mean
The data list shows the scores of ten students in Mr. Smith's math class. 61, 67, 81, 83, 87, 88, 89, 90, 98, 100
Mean = Sum of terms/Number of terms
Number of terms = 10
Mean = 61 + 67 + 81 + 83 + 87 + 88 + 89 + 90 + 98 + 100/10
Mean = 844/10
Mean = 84.4
Step 2
Standard deviation
The formula for sample standard deviation =
√(x - Mean)²/n - 1
= √[(61 - 84.4)² + (67 - 84.4)² + (81 - 84.4)² + (83 - 84.4)² + (87 - 84.4)² + (88 - 84.4)² + (89 - 84.4)² + (90 - 84.4)² + (98 - 84.4)² + (100 - 84.4)²]/10 - 1
=√ 547.56 + 302.76 + 11.56 + 1.96 + 6.76 + 12.96 + 21.16 + 31.36 + 184.96 + 243.36/10 - 1
= √1364.4/9
= √151.6
= 12.31259518
Approximately to the nearest tenth = 12.3
The standard deviation = 12.3
Answer:
2
Step-by-step explanation:
Using the distance formula,

We just need to plug in the numbers.
So 
Then we simplify it to

Finally, we get
, which is
when simplified.