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3 years ago

What is the product? (3a^2b^4)(-8ab^3)

Mathematics

2 answers:

topjm [15]3 years ago

7 0

Answer:

-24a^3 b^7

Step-by-step explanation:

(3a^2b^4)(-8ab^3)

Step 1: Multiply the coefficients

= -24a^2. b^4. a. b^3

Step 2: Using the exponent rule : a^m.a^n = a^(m +n)

If we have to the same base, we can add the powers.

Applying the rule, we get

= -24.a^(2 +1).b^(4 +3)

= -24a^3 b^7.

Answer is -24a^3 b^7.

Hope this will helpful.

Thank you.

sdas [7]3 years ago

5 0

-24a^3b^7 you multiply the two numbers and add the exponents.

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How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy

lisov135 [29]

Answer:

$300\; \rm lb$ .

Step-by-step explanation:

Let $x$ represent the mass (in pounds) of that $15\%$ copper alloy required, such that the final mixture would contain $25.5\%$ copper by mass.

Consider: if $x$ pounds of that $15\%$ copper alloy is mixed with $700$ pounds that $30\%$ copper alloy, what would be the mass of copper in the mixture?

Mass of copper in $x$ pounds of that $15\%$ copper alloy: $(0.15\, x)\; \rm lb$ .
Mass of copper in $700$ pounds of that $30\%$ copper alloy: $700 \times 0.30 = 210\; \rm lb$ .

Therefore, the mixture would contain $(210 + 0.15\, x) \; \rm lb$ of copper.

The mass of that mixture would be $(700 + x)\; \rm lb$ . The mass fraction of copper in that mixture would be:

$\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%$ .

This ratio is supposed to be equal to $25.5\%$ . These two pieces of equations combine to give an equation about $x$ :

$\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%$ .

$\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255$ .

Simplify and solve for $x$ :

$210 + 0.15\, x= 0.255\, (700 + x)$ .

$(0.255 - 0.15)\, x= 210 - 0.255 \times 700$ .

$\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300$ .

Therefore, $300\; \rm lb$ of that $15\%$ alloy would be required.

4 0

3 years ago

What is an equation of the line that passes through the points (6, -3) and<br> (-6, -5)?

SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

The standard form of an equation for a straight line is y=mx+b, where m is the slope and b is the y-intercept (the value of y when x = 0).

We can calculate the slope from the two given points, (6,-3) and (-6,-5). Slope is Rise/Run, where Rise is the change in y and Run is the change in x.

From the two given points, starting at (-6,-5) and going to (6,-3):

Rise = (-3 - (-5)) = +2

Run = (6 - (-6)) = 12

Rise/Run (slope) = 2/12 or 1/6

The equation becomes y = (1/6)x + b

We can find b by enterieng either of the two given points and solving for b. I'll pick (6,-3):

y = (1/6)x + b

-3 = (1/6)*(6) + b

-3 = 1 + b [Now you can see why I chose (6,-3)]

b = -4

The equation is y = (1/6)x - 4

Check this with a DESMOS graph (attached).

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3 years ago

Fred has 30 minutes to do a three-problem quiz. He spent 10 7/10 minutes on question a and 5 2/5 minutes on question b. How much

tatiyna

Answer:Fred has 13 9/10 minutes left for question C

Step-by-step explanation:

The total time that Fred has to do the three-problem quiz is 30 minutes.

He spent 10 7/10 minutes on question A. Converting 10 7/10 minutes to improper fraction, it becomes 107/10 minutes.

He spent 5 2/5 minutes on question B. Converting 5 2/5 minutes to improper fraction, it becomes 27/5 minutes.

Total time that Fred spent on question A and question B is

107/10 + 27/5 = (107 + 54)/10

= 161/10 minutes.

The amount of time that he has left for question C would be

30 - 161/10 = (300 - 161)/10 = 139/10

= 13 9/10 minutes

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Answer:

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kkurt [141]

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