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choli [55]
3 years ago
14

Felipe has ridden 48 miles of a bike course. The course is 60 miles long. What percentage did Felipe ridden so far

Mathematics
1 answer:
MatroZZZ [7]3 years ago
7 0

Answer:

58

Step-by-step explanation:

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Sin (5/6) show work for circle
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2 years ago
The school cafeteria seats 250 students. 203 students are already seated. Write and sole an inequality that represents the addit
Nitella [24]

Answer:

An equation that represents the given situation is 203+x=250 and the additional number of students that can be seated is 47

Step-by-step explanation:

Number of students already seated in school cafeteria = 203

Let x be the additional number of students that can be seated

So, Total number of seats available in school cafeteria = 203+x

We are given that the school cafeteria seats 250 students

So, 203+x=250

\Rightarrow x=250-203

\Rightarrow x=47

Hence an equation that represents the given situation is 203+x=250 and the additional number of students that can be seated is 47

6 0
3 years ago
How do mental math strategies help you solve problems such as the ones above?
Luden [163]

With mental math, you can perform equations quickly and efficiently. They also help you to develop your own strategies and solve more complex math equations. Hope this helps;)


7 0
3 years ago
Laura has a 5-digit combination lock on her briefcase and has forgotten the
TiliK225 [7]

Answer: 4000

Step-by-step explanation:

don’t have it just know that’s the answer

8 0
3 years ago
PLEASE HELP (30 POINTS) Solve the rational equation x/3 = x^2/x + 5 , and check for extraneous solutions.
anygoal [31]

Option C: x=0 and x=\frac{5}{2} are the solutions.

Explanation:

The equation is \frac{x}{3} =\frac{x^{2} }{x+5}

We shall determine the value of x, by simplifying the equation.

$\begin{aligned} x(x+5) &=3 x^{2} \\ x^{2}+5 x &=3 x^{2} \\ 2 x^{2}-5 x &=0 \\ x(2 x-5) &=0 \end{aligned}$

Thus, x=0 and x=\frac{5}{2} are the solutions.

Now, let us check whether the solutions are extraneous solutions.

Let us substitute x=0 in the original equation to check whether both sides of the equation are equal.

\begin{aligned}&\frac{0}{3}=\frac{0^{2}}{0+5}\\&0=\frac{0}{5}\\&0=0\end{aligned}

Thus, both sides of the equation are equal.

Hence x=0 is a true solution.

Now, Let us substitute x=\frac{5}{2} in the original equation to check whether both sides of the equation are equal.

\begin{aligned}\frac{\left(\frac{5}{2}\right)}{3} &=\frac{\left(\frac{5}{2}\right)^{2}}{\left(\frac{5}{2}\right)+5} \\\frac{5}{6} &=\frac{\left(\frac{25}{4}\right)}{\left(\frac{15}{2}\right)} \\\frac{5}{6} &=\frac{5}{6}\end{aligned}

Thus, both sides of the equation are equal.

Hence, x=\frac{5}{2} is a true solution.

Thus, solutions are not extraneous.

Hence, Option C is the correct answer.

8 0
3 years ago
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